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nata0808 [166]
3 years ago
11

Consider the compound Pb(SO4)2 and answer the following questions:

Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0
Hey there ! 

a)  Pb(SO4)2 => <span> lead(II) sulfate 


b) </span><span>The molar mass of this compound was calculated from the amount of atoms of each element, with its respective atomic masses

Pb = 207.2  a.m.u

S = 32.065 a.m.u

O = </span><span>15.9994 a.m.u

Therefore:

</span>Pb(SO4)2 = 207.2 + 32.065 * 2 + 15.9994 * 8 =>  <span>399.3252 g/mol
</span>
hope this helps!
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2. How many molecules are contained in 25 L of N₂ at S. T.P.?
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Explanation:

How many nitrogen molecules are in 1 liter of nitrogen gas at STP?

Answer

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Pete Gannett

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

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1 year ago
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I need someone to answer these.
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Answer:

The identity of an atom is determined my the number of <u>protons</u>. This is the <u>atomic number</u>.

The particle(s) found inside the nucleus are called <u>protons and neutrons</u>. Their combined mass is referred to as <u>the mass number</u>.

Isotopes have the same number of <u>protons</u>, but different number of <u>neutrons</u>.

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