This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.
Formula
V / T = V1 / T1
Givens
- V = 56.05 mL
- T = 315.1 degrees Kelvin
- V1 = x
- T1 = 380.5 degrees Kelvin
Solution
56.05/315.1 = x/380.5 Simplify the left.
0.1779 = x / 380.5 Multiply both sides by 380.5
0.1779 * 380.5 = 380.5x/380.5
67.68 mL = x This is your answer
E = hc/(lamda)
The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.
Plancks constant, h = 6.626×10^-32 J·s
Speed of light, c = 3.00×10^8 m/s
The energy must be greater than or equal to 1×10^-18 J
1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x
x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)
x ≤ 1.99×10^-7 m or 199 nm
The wavelength of light must be greater than or equal to 199 nm
Answer:
68 g
Explanation:
Molar mass (C10H16) = 10*12.0 g/mol + 16*1.0 g/mol = (120+16)g/mol =
= 136 g/mol
m (C10H16) = n(C10H16)*M(C10H16) = 0.5 mol*136 g/mol = 68 g
n(C10H16) - number of moles of C10H16
M(C10H16) - molar mass of C10H16
<span>magnesium oxide is a compound that is composed of one atom of magnesium and two atoms of oxygen. The compound is a combination of Mg2+ ion and O2-. The ions translate into atoms which reflects on the subscripst of the elements already. magnesium oxide is a basic oxide with the pH level greater than 7.</span>
Answer:
the amount of reactants is always directly proportional to the product
Explanation:
