4 years ago

Solve the equation using the method of completing the square 2x^2+16x-8=0

1 answer:

5 0

$2x^2+16x-8=0\\
x^2+8x-4=0\\
x^2+8x+16-20=0\\
(x+4)^2=20\\
x+4=\sqrt{20} \vee x+4=-\sqrt{20}\\
x=-4+2\sqrt5 \vee x=-4-2\sqrt5$

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pshichka [43]

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Step-by-step explanation:

Recall that the transformation T consists of a translation of 2 units to the right and 1 unit up. Then, T preserves distances(which means that it keeps distances between points the same as before applying the transformation). Then, distance CB is the sames as distance C'B'. We will use the distance formula: if we have points (x,y), (z,w) then the distance between them is given by

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