Question

Solve the equation using the method of completing the square 2x^2+16x-8=0

Answer 1

$2x^2+16x-8=0\\ x^2+8x-4=0\\ x^2+8x+16-20=0\\ (x+4)^2=20\\ x+4=\sqrt{20} \vee x+4=-\sqrt{20}\\ x=-4+2\sqrt5 \vee x=-4-2\sqrt5$