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SVETLANKA909090 [29]

3 years ago

10

The equation of a circle is given below. What is its center?

1 answer:

svp [43]3 years ago

6 0

Answer:

$( \frac{2}{3}, 0)$

Step-by-step explanation:

The general equation for a circle is

${(x - a) }^{2} + {(y - b) }^{2} = {r}^{2}$

Where a and b are the x and y values of the centre. So comparing to your equation you can see that a is 2/3 and b is 0

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Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

What us the range of the data below?

MArishka [77]

The range of the data is 12

3 0

2 years ago

Select the correct answer from each drop-down menu. Javier purchased a digital camera for $384. The value of the camera deprecia

Eva8 [605]

Answer:

it will take 3 yrs for the value of camera to reach $162.

Step-by-step explanation:

<u>Pd</u><u> </u><u>=</u><u> </u><u>P</u><u>(</u><u>1</u><u>-</u><u>R</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>

<u>1</u><u>6</u><u>2</u><u> </u><u>=</u><u> </u><u>3</u><u>8</u><u>4</u><u>(</u><u>1</u><u>-</u><u>2</u><u>5</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>

<u>1</u><u>6</u><u>2</u><u>/</u><u>3</u><u>8</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>

<u>2</u><u>7</u><u>/</u><u>6</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>

<u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>3</u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>

<u>T</u><u> </u><u>=</u><u> </u><u>3</u>

3 0

2 years ago

Find the area using the given image.

ArbitrLikvidat [17]

Answer:

4.

Step-by-step explanation:

Area = 1/2 * base + height

= 1/2 * 2 * 4

= 4 unit^2.

3 0

2 years ago

(50 POINTS AND BRAINLIEST!)

topjm [15]

Answer:

type of angles is complementary

equation is (3x-5)+x=90

x=23.75

8 0

3 years ago