Iodine dissolves easily in chloroform and hexane but does not dissolve in water. When polar and non-polar are mixed, water finds other water and forms spherical bubbles. When mixed with hexane, the iodine molecules experience London dispersion forces. There is no induced polarity in the iodine molecules and they exhibit their typical violet color in the solution. (Note: The color may be pink if the iodine concentration is low.) Hope this helps!!
Answer:
See explanation
Explanation:
The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.
Now let us take the journey;
R2O3- refers to an oxide of a group 13 element, eg Al2O3
R2O - refers to an oxide of group a group 1 element e.gNa2O
RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2
RH2 - refers to the hydride of a group 12 element Eg CaH2
R2O7 - refers to an oxide of a group 17 element E.g Cl2O7
RH3- refers to a hydride of a group 13 element E.g AlH3
Answer: Option D) 0.902M
Explanation:
Sodium chloride has a chemical formula of NaCl
Given that,
Amount of moles of NaCl (n) = ?
Mass of NaCl in grams = 145g
For molar mass of NaCl, use the molar masses:
Sodium, Na = 23g;
Chlorine,Cl = 35.5g
NaOH = (23g + 35.5g)
= 58.5g/mol
Since, amount of moles = mass in grams / molar mass
n = 145g / 58.5g/mol
n = 2.48 mole
Amount of moles of NaCl (n) = 2.48 mole
Volume of NaCl solution (v) = 2.75L
Concentration of NaCl solution (c) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
c = 2.48 mole / 2.75L
c = 0.9018M
Approximately, c = 0.902M
[c is the concentration in moles per litres which is also known as molarity]
Thus, the molarity of the solution is 0.902M
Answer:
c-gamma decay
Explanation:
In gamma decay, neither the atomic number or the mass number is changed