Answer:
0.263 mol
Explanation:
K2SO4 - potassium sulfate
Molar mass (K2SO4) = 2*39.0983 + 32.065 + 4*15.9994 =
= 174.2592≈174.26 g/mol
45.8 g * 1 mol/174.26 g = 0.263 mol
Answer:
The electrochemical synthesis of ammonia from nitrogen under mild conditions using renewable electricity is an attractive alternative to the energy-intensive Haber–Bosch process, which dominates industrial ammonia production.
Explanation:
However, there are considerable scientific and technical challenges facing the electrochemical alternative, and most experimental studies reported so far have achieved only low selectivities and conversions. The amount of ammonia produced is usually so small that it cannot be firmly attributed to electrochemical nitrogen fixation rather than contamination from ammonia that is either present in air, human breath or ion-conducting membranes, or generated from labile nitrogen-containing compounds (for example, nitrates, amines, nitrites and nitrogen oxides) that are typically present in the nitrogen gas stream, in the atmosphere or even in the catalyst itself. Although these sources of experimental artefacts are beginning to be recognized and managed, concerted efforts to develop effective electrochemical nitrogen reduction processes would benefit from benchmarking protocols for the reaction and from a standardized set of control experiments designed to identify and then eliminate or quantify the sources of contamination.
pH. 10 because it is strong base
Shift to reactants(left)
<h3>Further explanation
</h3>
A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.
The buffer solution can be acidic or basic
Acid buffer solutions consist of weak acids and their salts.
A buffer solution of NaC2H202 and HC2H2O2 (acetic acid) is included in the acid buffer
So :
a slight addition of acid (H⁺) will be balanced by the conjugate base
the addition of a small base (OH⁻) will be balanced by the weak acid
With the addition of acid (H +), the equilibrium will shift to the left, in the formation of CH3COOH. The added acid will be neutralized by the conjugate base component (CH3COO−).
The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.
Volume is inversely proportional to the rate of reaction.
As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.
Let's consider a reaction A → B.
r is rate of reaction and K is rate constant, A is the concentration of reaction.
r = k(A)
r is directly proportional to the A.
But the concentration of A is in Moles/liters (i.e. moles per unit volume)
r is inversely proportional to the volume of vessel or chamber.
Hence as volume increases rate of reaction decreases.
For study more about reaction rate refer following link brainly.com/question/19513092.
#SPJ1.
