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elena-s [515]
3 years ago
12

What is the probability of drawing 2 cards in succession (without replacement) from a standard deck and having them both be face

cards?
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:      \dfrac{11}{221}

Step-by-step explanation:

We know that the total number of cards in a standard deck = 52

Then the number of ways to draw any two card = 52 x (52-1)

= 52 x 51 = 2652   [By Multiplicative principle]

Also , there are 12 face cards in a standard deck , so the number of ways to draw two face cards in succession = 12 x (12-1)

12 x 11= 132   [By Multiplicative principle]

Then, the probability of drawing 2 cards in succession (without replacement) from a standard deck and having them both be face cards would be

\dfrac{\text{ Number of ways to draw 2 face cards}}{\text{Total number of ways to draw two cards}}

=\dfrac{132}{2652}=\dfrac{11}{221}

Hence, the required probability is  \dfrac{11}{221} .

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The sum of two numbers is 120. Three times
alexgriva [62]

Answer:

The answer is 68 and 52

Step-by-step explanation:

x + y = 120

3(x - y ) = 48

We have 3x + 3y = 360

and 3x - 3y = 48

Adding we have the following:

6x = 408

x = 68

y = 120-48 = 52

6 0
3 years ago
What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of
Mrrafil [7]

Answer:

\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be (x_1,y_1)\,,\,(x_2,y_2) such that the point p(x,y) divides KJ in ratio m:n

Then coordinates of point  P are given by \left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )

Take m:n=3:5

So,

coordinates of point P = \left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

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2 years ago
In sporting tournaments, teams are eliminated after they lose. The number of teams in the
tresset_1 [31]

38 teams started.

16×3=38

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2 years ago
ANSWER ASAP What is the volume of this right triangular prism? A. 180 cubic centimeters B. 120 cubic centimeters C. 90 cubic cen
Bess [88]

Volume of the right triangular prism 90 cube cm.

Step-by-step explanation:

Given,

In the right triangular prism

Length (l) = 6 cm

Base (b) = 5 cm

Height (h) = 6 cm

To find the volume of the right triangular prism

Formula

Volume of the right triangular prism = \frac{1}{2}bhl

Now,

Volume of the right triangular prism = \frac{1}{2}×6×6×5 cube cm

= 90 cube cm

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3 years ago
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