uhm I can't help with that... sorry
1 step (B): raise both sides of the equation to the power of 2.
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2 step (A): simplify to obtain the final radical term on one side of the equation.
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3 step (F): raise both sides of the equation to the power of 2 again.
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4 step (E): simplify to get a quadratic equation.
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5 step (D): use the quadratic formula to find the values of x.
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6 step (C): apply the zero product rule.
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Additional 7 step: check these solutions, substituting into the initial equation.
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
You will be adding 4 to the x-axis because it is positive, to go left you would subtract. Then you would be subtracting 2 to the y axis because you are going down. To go up you would add.
A(0,0)
+4,-2
A'(4,-2)
B(2,0)
+ 4,-2
B'(6,-2)
C(3,4)
+4,-2
C'( 7,2)
D(0,4)
+4,-2
D'(4,2)
Answer:
∠C ∠D
82° 98°
132° 48°
115° 65°
25° 155°
Step-by-step explanation:
180 -82 = 98
180 - 132 = 48
180 - 115 = 65
180 - 25 = 155