Question

HELP ME PLZ ASAPPPPPP

Answer 1

Answer:

$(x,y) =(-4,-3)$ --- Vertex

$x = -4$ --- Axis of symmetry

Step-by-step explanation:

Given

$y = -6(x + 4)^2 - 3$

Solving (a): The vertex

For an equation written in

$y = a(x - h)^2 + k$

The vertex is:

$(x,y) = (h,k)$

By comparison:

$y = a(x - h)^2 + k$  and $y = -6(x + 4)^2 - 3$

$-h =4$       $k = -3$

$h =-4$         $k = -3$  

So, the vertex is:

$(x,y) =(-4,-3)$

Solving (b): The axis of symmetry

For an equation written in

$y = a(x - h)^2 + k$

The axis of symmetry is:

x = h

In (a):

$h =-4$

So:

$x = -4$