Which pair of triangles can be proven congruent by the HL theorem

Mathematics

2 answers:

Lelu [443]3 years ago

7 0

Answer: Third pair

Step-by-step explanation:

The HL theorem says that if the hypotenuse and a leg of one right triangle are equal to the hypotenuse and a leg of another right triangle, then the triangles are said to be congruent.

From the given pictures only third pair of triangles have hypotenuse and one leg are equal.

Then by HL theorem, the triangles in third pair are congruent.

lys-0071 [83]3 years ago

4 0

third one is your answer

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There is no solution to the equation cscx=0.<br> True or False

Svetradugi [14.3K]

Answer:

True

Step-by-step explanation:

First, we need to recognize that

$csc(x)=\frac{1}{sin(x)}$

Now, we can try to solve

$\frac{1}{sin(x)} =0$

Multiply each side by $sin(x)$

$1=0*sin(x)\\\\1=0$

As we end up with an answer that cannot be true, we know that there is no solution.

Another method to solve this would be graphing the function $y=csc(x)$

When graphed, it can be seen that there is an asymptote at x=0 meaning that there is no value for x=0.

4 0

2 years ago

Read 2 more answers

Sara is trying to find an equation for a line that passes through (5, 2) and is perpendicular to 3x + 2y = 15. Explain the steps

Anettt [7]

Not on your list, but an easy way is
.. a) swap coefficients of x and y, negating one. (Now you have 2x -3y.)
.. b) set any constant term to zero (now you have 2x -3y = 0)
.. c) translate the line to the point (5, 2) by substituting x ⇒ x-5, y⇒ y-2
2(x -5) -3(y -2) = 0

The way you've been taught, selection C is the proper choice.