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Lana71 [14]
3 years ago
6

Which pair of triangles can be proven congruent by the HL theorem

Mathematics
2 answers:
Lelu [443]3 years ago
7 0

Answer: Third pair

Step-by-step explanation:

  • The HL theorem says that if the hypotenuse and a leg of one right triangle are equal to the hypotenuse and a leg of another right triangle, then the triangles are said to be congruent.

From the given pictures only third pair of triangles have hypotenuse and one leg are equal.

Then by HL theorem, the triangles in third pair are congruent.

lys-0071 [83]3 years ago
4 0

third one is your answer

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Nina [5.8K]

Answer:

B(7,10)

Step-by-step explanation:

M(5,7)=(x ,y)\\A(3,4)=(x_1,y_1)\\B(x_2,y_2)\\\\Endpoint ;\\x = \frac{x_1+x_2}{2}\\ \\5 = \frac{3+x_2}{2}\\ Cross\:Multiply\\5\times 2 =3+x_2\\10=3+x_2\\10-3 =x_2\\7=x_2\\\\\\y = \frac{y_1+y_2}{2} \\\\7 = \frac{4+y_2}{2}\\ Cross\:Multiply\\7\times 2 =4+y_2\\14 =4+y_2\\14-4 =y_2\\10 =y_2\\\\\\B(7,10)

5 0
3 years ago
Please answer fast !!
Alborosie

Answer:

x=2

Step-by-step explanation:

2*2-x=2

4-x=2 subtract 4 by both sides

-x= -2 multiply each side by -1

x=2   answer

3 0
2 years ago
What is the sign of the product (3)(–3)(–2)(4)?
Ilia_Sergeevich [38]

Answer:

A)

Step-by-step explanation:

6 0
3 years ago
K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

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2K=mv^2

Divide by m to isolate v^2.

\frac{2K}{m}=\frac{mv^2}{m}

\frac{2K}{m} =v^2

To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

4 0
3 years ago
(5x - 18) + (4x + 7) = 180 what is the value of x?
CaHeK987 [17]
(5x-18)+(4x+7)=180
5x+4x=180+18-7
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Answer: x=191/9
7 0
3 years ago
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