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lys-0071 [83]
3 years ago
5

The answers sis i need help

Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0

what question are you wanting to be answered?


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Don’t get this at all...
Dima020 [189]

Answer:

P.E.M.D.A.S

P: parenthesis

E: exponent

M: multiplication

D: division

A: addition

S; subtraction

the question E: Addition and subtraction

the question F: Multiplication and division

5 0
3 years ago
In a packet of stickers there are 15 small stars, 7 big stars, 9 small rockets, and 6 big rockets. Kevin is going to choose one
yanalaym [24]

Answer:

31/37

Step-by-step explanation:

There are 15 + 7 + 9 + 6 = 37 total stickers. Of those, 15 + 9 = 24 are small and 15 + 7 = 22 are stars. However, there are 15 small stars so 24 - 15 = 9 of them are only small and 22 - 15 = 7 are only stars. This means that there are 15 + 9 + 7 = 31 stickers that are small or stars, therefore the probability is 31/37.

4 0
3 years ago
FREE POINTS!!!!!! Enjoy :33333333
Lelechka [254]

Answer:

ok thanks i guess

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Put together, Albert and Jason have
Anon25 [30]

Answer:

Step-by-step explanation:

you have to subtract 110 by 42 then when you have that number you divide it by two. then you add 42 to one of the twin numbers. That will be how many jason has, and albert will have the other number you kept the same.

7 0
3 years ago
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
3 years ago
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