How to write 0.917 in expanded form

Mathematics

2 answers:

Mademuasel [1]3 years ago

5 0

The expanded form of 0.917 is 0.+.900+.10+.7

SCORPION-xisa [38]3 years ago

5 0

Answer:

$0.9+0.01+0.007$

Step-by-step explanation:

We are asked to write 0.917 in expanded form.

We can see that our given number has 9 tenths, 1 hundredths and 7 thousandths.

To write our given number in expanded form, we will write each digit according to its place value as:

$0.917=0.9+0.01+0.007$

Therefore, the expanded form of our given number would be $0.9+0.01+0.007$ .

You might be interested in

leona has three dollars less than skye. together they have 17 dollars. how much money does skye have?

Fynjy0 [20]

L has "x -3"
S has "x"

x + x - 3 = 17

2x -3 (+3) = 17 (+3)

2x = 20

2x/2 = 20/2

x = 10

Leona has x - 3, or 10 - 3, or 7 dollars
Skye has 10 dollars

hope this helps

5 0

3 years ago

A square has sides that are 80 ft long. Which equations can be used to calculate d the length of a diagonal of the square in fee

LenKa [72]

Notice the picture below

just use the pythagorean theorem to ge the diagonal

$\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}$

7 0

3 years ago

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .