A) blue/total = (3+2)/(8+2) = 5/10 = 50%
b) blue/total = (3)/(8 +2) = 3/10 = 30%
When multiplying fractions just multiply the numerator and denominators together, then simplify the fraction you get.
To solve the addition problem, first convert 2 and 1/2 to an improper fraction. It should be 5/2. Now 3/8 and 5/2 must be added together.
To add these, they must have the same denominator. Let's give 5/2 a denominator of 8, so it matches 3/8.
To give 5/2 a denominator of 8, you are starting with a denominator of 2. 2 × 4 = 8, so you must multiply 5/2 by 4.
You should get 20/8. Now you have to add 20/8 and 3/8. The only thing you add is the numerator, so you should get 23/8 as a final answer.
For the subtraction problem, do these same steps to make the fractions you must subtract have the same denominator, then subtract only the numerator to get the answer. Once you solve the subtraction problem, text me what you got so I can check it for you. :)
Answer:
![\sqrt[5]{a^{3} b^{2}c}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%7D)
Step-by-step explanation:
Rationalization factor of ![\sqrt[5]{a^2 b^3 c^4}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B5%5D%7Ba%5E2%20b%5E3%20c%5E4%7D%20)
![= \sqrt[5]{a^{5-2} b^{5-3}c^{5-4}}\\= \sqrt[5]{a^{3} b^{2}c^{1}}\\= \sqrt[5]{a^{3} b^{2}c}\\](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B5-2%7D%20b%5E%7B5-3%7Dc%5E%7B5-4%7D%7D%5C%5C%3C%2Fp%3E%3Cp%3E%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%5E%7B1%7D%7D%5C%5C%3C%2Fp%3E%3Cp%3E%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%7D%5C%5C%20)
<span>hypothesis :-
if x=30, then 3/4x+5≠20
let Q:- x=30 P:- 3/4x+5≠20
we need to prove if Q then P (Q →P)
proof :-
lets assume 34x+5=20 is true
now x=30
so
3/4(30)+5=27.5 ≠20
which is a contradiction
proved ^</span>
