What is the approximate area of the shaded region?
2 answers:
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Answer:
The null hypothesis is:
The alternative hypothesis is:
Step-by-step explanation:
At the null hypothesis, we test if the mean is equal to a certain value.
At the alternate hypothesis, we test if the mean is less than, more than, or different from the value tested at the null hypothesis.
The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of 20 lb.
This means that the null hypothesis is:
Could it be that the average tuft strength is above 100 lb?
The world above means that the appropriate alternative hypothesis is:
The complete question in the attached figures
we know that
1 ft---------------> 0.083333 in
so
<span>24 inches high--------------> 24*0.083333=2 ft
</span><span>36 inches wide--------------> 36*0.083333=3 ft
</span><span>we will analyze each drawing
</span><span>
drawing a) scale 1/4 in/ 1 ft ----------> (1/4)/1=1/4
for a high of 2 ft-------------> 2*(1/4)=0.5 in
f</span>or a wide of 3 ft-------------> 3*(1/4)=0.75 in
drawing a) is not solution
drawing b) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing b) is not solution
drawing c) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing c) is not solution
drawing d) scale 1 in/ 1 ft ----------> (1)/1=1
for a high of 2 ft-------------> 2*(1)=2 in
for a wide of 3 ft-------------> 3*(1)=3 in
drawing d) is a solution
the answer is
The correct model of the flag is the drawing D
we know that
1 ft---------------> 0.083333 in
so
<span>24 inches high--------------> 24*0.083333=2 ft
</span><span>36 inches wide--------------> 36*0.083333=3 ft
</span><span>we will analyze each drawing
</span><span>
drawing a) scale 1/4 in/ 1 ft ----------> (1/4)/1=1/4
for a high of 2 ft-------------> 2*(1/4)=0.5 in
f</span>or a wide of 3 ft-------------> 3*(1/4)=0.75 in
drawing a) is not solution
drawing b) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing b) is not solution
drawing c) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing c) is not solution
drawing d) scale 1 in/ 1 ft ----------> (1)/1=1
for a high of 2 ft-------------> 2*(1)=2 in
for a wide of 3 ft-------------> 3*(1)=3 in
drawing d) is a solution
the answer is
The correct model of the flag is the drawing D