<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
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Hence, BC=DC proved.
Answer:
$45.00
Step-by-step explanation:
it's the same thing, there is no context, so it pushes for me to believe that the answer is the same
The (x + 4) tells you that the function is moving 4 units to the left.
the answer would be letter C
Answer:
False
Step-by-step explanation:
To solve this problem, plug in the value for Y, 9, into the inequality.
9 + 3 < 12
Now, solve the inequality. Evaluating 9 + 3, the equation becomes:
12 < 12
12 is not less than 12 (12 = 12), therefore the answer is false.
Answer:
Step-by-step explanation:
If you have a calculator do pie times radius squared times height. So basically pie times 25 squared times 40