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Ira Lisetskai [31]
3 years ago
14

What is the GCF of 30b^2, 80b^2, and 20b^3?

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0
30b^2, 80b^2, \ and \ 20b^3

30b^2 = 10b^2(3)

80b^2 = 10b^2(8)

20b^3 = 10b^2(2b)

\text {GCF = } 10b^2



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n(n + 1)  = 2*630

n(n + 1)  = 1260

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n² + n - 1260 = 0

By trial an error note that 1260 = 35 * 36

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Replace n with 36n - 35n

n² + 36n - 35n - 1260 = 0

n(n + 36) - 35(n + 36) = 0

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n = 0 - 36,   or  n = 0 + 35

n = -36, or 35

n can not be negative. 

n = 35 is valid.

Since n is a positive whole number, that means 630 is a triangular number.

So the answer is True.
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