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blagie [28]
3 years ago
12

In a bag full of candy, 1/4 of these are green, 1/8 are blue, 1/12 are yellow and the remaining 26 white. How many candies are b

lue?
Mathematics
1 answer:
igomit [66]3 years ago
4 0

In a bag of balls, 1/4th are green, 1/8th are blue, 1/12th are yellow and the remaining 26 are white. How many balls are blue?

There are 4 colours of balls - green, blue, yellow and white.

Add (1/4)+(1/8)+(1/12) = (6/24)+(3/24)+(2/24) = 11/24 so the balance or (24–11)/24 = 13/24 = 26 white. Hence the total number of balls are 2*24 = 48.

Of the 48 balls, green are (1/4)*48 = 12, blue are (1/8)*48 = 6, yellow are (1/12)*48 = 4 and the rest, white are 26.

Check: Total number of balls = 12+6+4+26 = 48

Answer: 6 balls are blue.

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You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

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Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

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