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2 years ago

What is the volume of a sphere with the radius of 4 inches? use 3.14 for pi

Mathematics

1 answer:

harkovskaia [24]2 years ago

5 0

Answer: 268.1

Step-by-step explanation:

V = (4/3) 3.14 (4) to the power of 3

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A can is 7 inches high and has a radius of 2 inches,

Yuliya22 [10]

Answer:

87.92 cubic inches

Step-by-step explanation:

to find the volume of a cylinder the formula is V = $\pi$ $r^{2}$ h

so first i squared 2

2x2= 4

i then multiplied 4 by the height (7)

4x7 = 28

then times 28 by pi (3.14)

28x 3.14 = 87.92

4 0

2 years ago

X=4, y= -7, z=9 solve: -2x-3y+z

vesna_86 [32]

Answer:

Step-by-step explanation:

To solve this we can plug the values in.

-2x-3y+z

-2(4)-3(-7)+(9)

Simplify.

-8+21+9

Add.

8 0

2 years ago

PLEASE HELP

MAXImum [283]

The answer is x=34 degrees.

6 0

2 years ago

Read 2 more answers

Integrate G(x,y,z)equalsz over the parabolic cylinder yequalszsquared, 0less than or equalsxless than or equals2, 0less than

yKpoI14uk [10]

I gather you're supposed to compute the integral of $G(x,y,z)=z$ over a surface $S$ that is the part of the parabolic cylinder $y=z^2$ with $0\le x\le2$ and $0\le z\le\frac{\sqrt{15}}2$ .

We can parameterize $S$ by

$\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k$

with the given constraints on $x$ and $z$ . Take the normal vector to $S$ to be

$\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k$

so that the surface element is

$\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz$

Then in the integral, we have

$\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}$

5 0

2 years ago

Consider the following system of equations:

Kobotan [32]

Answer:

x=-15, y=25. (-15, 25).

Step-by-step explanation:

2x+3y=45

x+y=10

--------------

x=10-y

2(10-y)+3y=45

20-2y+3y=45

20+y=45

y=45-20

y=25

x+25=10

x=10-25

x=-15

5 0

2 years ago

Read 2 more answers