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Zigmanuir [339]
3 years ago
12

Question. if eli is guessing when he chooses a super bowl winner (that is, he mentally flips a fair coin to decide which team he

chooses as the winner), what is the probability that eli chooses 7 winners in a row
Mathematics
2 answers:
kolbaska11 [484]3 years ago
7 0

Answer:

The probability of 7 winners in a row = 1 / 128.

Step-by-step explanation:

That would be (1/2)^7 . The probabilities are multiplied because the events ( heads or tails) are independent.

Kaylis [27]3 years ago
3 0

Answer:

Step-by-step explanation:Proner26 Top Answerer

Answer:

The probability of 7 winners in a row = 1 / 128.

Step-by-step explanation:

That would be (1/2)^7 . The probabilities are multiplied because the events ( heads or tails) are independent.

Read more on Brainly.com - brainly.com/question/12307315#readmore

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Answer:

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Step-by-step explanation:

gggggggggggggggggggg

7 0
4 years ago
I need help with number 9 and 10 please thank you
Doss [256]

Answer:

54 gallons is 216 quarts, Hope this helps!

Step-by-step explanation:

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4 years ago
A quality report for a production line shows a score of 59 points on a 65-point inspection test. A passing score is 95% complian
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Step-by-step explanation:

5 0
3 years ago
UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of
11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

<u><em>Let </em></u>\mu<u><em> = population average time someone spends in the gym</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu = 56 minutes   {means that the average time someone spends in the gym is 56 minutes}

<u>Alternate Hypothesis</u>, H_A : \mu\neq 56 minutes   {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average time someone takes in the gym = 50 min

              \sigma = population standard deviation = 8 minutes

              n = sample of gym goers = 32

So, <em><u>test statistics</u></em>  =   \frac{50-56}{\frac{8}{\sqrt{32} } }

                               =  -4.243

<em>Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0
3 years ago
What is the scale factor in the dilation?
Bumek [7]

The scale factor of the given dilation is 3.

Step-by-step explanation:

Step 1:

In order to determine the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In the given graph, the preimage has a length of 3 units while the image has a length of 9 units.

Step 2:

So here the measurement after scaling is the length of the image which is 9 units and the measurement before scaling is the preimages length of 3 units.

The scale factor =\frac{9}{3} = 3.

So the scale factor is the third option 3.

8 0
3 years ago
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