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PolarNik [594]
2 years ago
5

What is an equation of the line that passes through the point (−4,−6) and is perpendicular to the line 2x-y=6?

Mathematics
1 answer:
slega [8]2 years ago
8 0

Answer:

y= -1/2x-8    Please see the file for better detail!

Step-by-step explanation:

To find the slope of the perpendicular line you have to find the opposite reciprocal, which means flip the number and give a negative because the original slope is positive. Please see the image for better detail. Use point slope, slope intercept forms to find your answer.

Download pdf
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What is x? The degree of the angle of x
irga5000 [103]

Answer:

x = 60°

Step-by-step explanation:

All the angles in a triangle add up to 180°. So, you have this equation.

87° + 33° + x = 180°

120° + x = 180°

x = 60°

The measure of angle x is 60°.

Hope that helps.

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2 years ago
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Step-by-step explanation:

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Pls need help, will give brianlist
Firdavs [7]

Answer:

1) Your slope should be 1/5

2) Your slope should be \frac{-3}{2}

3) Your slope should be 1/2

I hope this helps! : )

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Step-by-step explanation:

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2 years ago
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What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
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