What is the answer of 4 6/7?

Find the measure of angle 2 if the measure of angle 8 is 40<br> degrees.

Vinvika [58]

Answer:

what is the shape?

Step-by-step explanation:

like is a square triangle or what ? show us a picture

8 0

3 years ago

How many cats does a woman have when she gives the answer seven-eighths of my cats plus four. I can't determine how to work this

vichka [17]

X = 7/8x + 4
x - 7/8x = 4
8/8x - 7/8x = 4
1/8x = 4
x = 4*8
x = 32

7 0

3 years ago

NEED HELP!!!!! ASAP THANK YOU SO MUCH!!!!! What figure is a dilation of Figure A by a factor of 3?

Fynjy0 [20]

Answer:

the figure on the top left

Step-by-step explanation:

Hey There!

If figure a was going to be dilated by a scale factor of 3 you would have to multiply all of its dimensions by 3

the top length would be 6

the bottom length would be 9

the right side length would be 12

and the left side length would be 9

The first figure has all of these dimensions thus it is correct answer

6 0

3 years ago

Plz answer this question quickly

garri49 [273]

The answer is HC, HT, HH, CC, CT, CH, TC, TT, TH

7 0

4 years ago

A cake is removed from a 310°F oven and placed on a cooling rack in a 72°F room. After 30 minutes the cake's temperature is 220°

Fynjy0 [20]

Answer:

The time is 135 min.

Step-by-step explanation:

For this situation we are going to use Newton's Law of Cooling.

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium and is given by

$T(t)=C+(T_0-C)e^{kt}$

where,

C = surrounding temp

$T(t)$ = temp at any given time

t = time

$T_0$ = initial temp of the heated object

k = constant

From the information given we know that:

Initial temp of the cake is 310 °F.
The surrounding temp is 72 °F.
After 30 minutes the cake's temperature is 220 °F.

We want to find the time, in minutes, since the cake's removal from the oven, at which its temperature will be 100°F.

To do this, first, we need to find the value of k.

Using the information given,

$220=72+(310-72)e^{k\cdot 30}\\\\72+238e^{k30}=220\\\\238e^{k30}=148\\\\e^{k30}=\frac{74}{119}\\\\\ln \left(e^{k\cdot \:30}\right)=\ln \left(\frac{74}{119}\right)\\\\k\cdot \:30=\ln \left(\frac{74}{119}\right)\\\\k=\frac{\ln \left(\frac{74}{119}\right)}{30}$

$T(t)=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}$

Next, we find the time at which the cake's temperature will be 100°F.

$100=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}\\72+238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=100\\238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=28\\e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=\frac{2}{17}\\\ln \left(e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}\right)=\ln \left(\frac{2}{17}\right)\\\frac{\ln \left(\frac{74}{119}\right)}{30}t=\ln \left(\frac{2}{17}\right)\\t=\frac{30\ln \left(\frac{2}{17}\right)}{\ln \left(\frac{74}{119}\right)}\approx 135.1$

4 0

3 years ago