All categories

3 years ago

Which of the following are solutions to the equation below?

Mathematics

1 answer:

salantis [7]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

You might be interested in

3x^2+5x-3 solve for x using quadratic formula

Anna11 [10]

substitute the values from the quadratic formula.

a= 3

b= -5

c= -3

simplify the numerator

5±√61/2 times 3

Multiply 2 by 3

<h2>ANSWER:5±√61/6</h2>

3 0

3 years ago

What are the coordinates of quadrilateral A'B'C'D'?

Andrei [34K]

0,3 3,3 2,3 and 1,2 (from A to D)

8 0

3 years ago

Suppose that an individual has a body fat percentage of 15.9% and weighs 159. How many pounds of her weight is made up of fat? R

Anna007 [38]

Answer:

25.3 lb

Step-by-step explanation:

We can multiply the whole by the percentage to find the part. Since 15.9% is equal to 0.159, the weight of fat is 159*0.159 = 25.281. Round this to the nearest tenth, and we get 25.3 pounds.

5 0

2 years ago

Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many poss

egoroff_w [7]

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

In this problem

The probability of choose a blue card is

$x=7$

$y=7+4+6+8=25$

substitute

$P=\frac{7}{25}$

The probability of choose a green card is

$x=4$

$y=7+4+6+8=25$

substitute

$P=\frac{4}{25}$

The probability of choose a red card is

$x=6$

$y=7+4+6+8=25$

substitute

$P=\frac{6}{25}$

The probability of choose a yellow card is

$x=8$

$y=7+4+6+8=25$

substitute

$P=\frac{8}{25}$

The sum of the probabilities of the 4 possible outcomes is equal to

$\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25}$ ----> represent the 100%

4 0

3 years ago

Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms

Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 , r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x) → θ₁ = tan⁻¹ (4/3)= 0.927 rad , θ₂ = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0

3 years ago