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2 years ago

A flying object is moving at 150 m/s. It makes a complete and final stop in 12 seconds. Calculate the object’s acceleration.

Mathematics

1 answer:

kondaur [170]2 years ago

4 0

Answer:

-12.5 m/s²

Step-by-step explanation:

v (final velocity) = 0

u (intial velocity) = 150 m/s

t = 12s

a= v-u/t

a = 0 - 150 / 12

a = -12.5 m/s²

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2 years ago

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2 years ago

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. 8cotθ + 3 = 5

galina1969 [7]

Answer:

θ = 76°

Explanation:

The given equation is:

8 cotθ + 3 = 5

8 cotθ = 5-3

8 cotθ = 2

cot θ = $\frac{2}{8} = \frac{1}{4}$

Now, we find θ

We know that the cot function is the inverse of the tan function.

The tan of an angle is positive in the first and third quadrants, therefore, the cot will be positive in the first and third quadrants as well

Now, we are given the condition:

0° ≤ x ≤ 90°

Therefore, we know for sure that our angle is in the first quadrant

θ = cot⁻¹( $\frac{1}{4}$ ) = 75.96° = 76° to the nearest degree

Hope this helps :)

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3 years ago

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