You need to find the amount subject to withholding, subtracting from the weekly salary the amount for one withholding allowance for weekly salaries, which is 77.90$:
830 - 77.90 = 752.1 $.
Then, look in the Fed Tax tables (
http://www.opers.ok.gov/Websites/opers/images/pdfs/2016-Fed-Tax-Tables.pdf ) for a married person with a weekly payroll.
You previously found an amount of 752.1 which is greater than 521 but less than 1613$: therefore the income tax to withhold is 35.70$ + 15% of excess over $521.
Therefore, calculate the income tax due: 35.70 + (752.1 - 521) × 15 ÷ 100 = 70.37$
The total amount of income tax that will be withheld is 70.37$
The answer is >>> 4 989 600
Answer:
The cost of one unit of electricity is $0.185
Step-by-step explanation:
Amount charged = $120.99
Units of electricity used = 654
The cost of a unit of electricity can be determined by dividing the amount charged by the number of units used.
So that,
cost of one unit of electricity = 
= 0.185
cost of one unit of electricity = $0.185
This implies that the cost of electricity used is charged at $0.185 per unit.
Thus for 654 units of electricity used, the cost would be;
654 x $0.185 = $120.99