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svp [43]
3 years ago
5

What is pie when it is round it to a 100

Mathematics
1 answer:
Degger [83]3 years ago
3 0
Well I think it is 3.14
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Can anyone help me with this math question please I will give brainlist!!
Juli2301 [7.4K]

Answer:

it's (4,4) since the point is right on top of (4,6) and by doing that it would make a closed quadrilateral

Step-by-step explanation:

it would be best to plot your points and whichever it lands on would be your next point.

5 0
2 years ago
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Determine the area of the figure.
LekaFEV [45]

Answer: 3x - 6 (in^2)

Step-by-step explanation:

base * height / 2

=

3 ( 2x - 4) / 2 (in^2)

= 3x - 6 (in^2)

5 0
1 year ago
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The measure of b is ___ ?
Evgen [1.6K]

Answer:

21

Step-by-step explanation:

Use Pythagorean Theorem

If you are looking for leg given the other sides of the right triangle: just do bigger square minus small square

and take square root

so 29^2 - 20^2

And then sqrt it!

sqrt(29^2-20^2)

21

3 0
3 years ago
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Emily wants to know the volume of a beach ball. She deduces that the beach ball has diameter of 12 inches, and then uses the fol
Over [174]

Answer:

D. She used the beach's ball's diameter when she should have used the radius

Step-by-step explanation:

To find the volume of the beach ball, using the volume of a sphere is the right formula to use, which is ⁴/3πr³.

The formula she used is correct.

Since the diameter of the ball is assumed to be 12 inches, what is needed to find the volume is the radius.

Radius (r) = ½(diameter) = ½(12) = 6 in.

This is where Emily made a mistake.

She used the diameter of the beach ball instead of its radius (r) which is needed in the equation.

She should have gotten,

V = ⁴/3(3.14)(6)² = 904.32 cubic inches

7 0
2 years ago
a pyramid has a regular hexagonal base with side length of 4 and a slant height of 6. what is the total area of the pyramid
Stels [109]
So hmm notice the picture below

the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges

now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}\cdot  n\cdot  s^2\cdot  cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of a side}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
n=6\\
s=4
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot  6\cdot  4^2\cdot  cot\left( \frac{180}{6} \right)

now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both

8 0
3 years ago
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