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r-ruslan [8.4K]
2 years ago
7

Resolva a expressão: 6÷3+2•7

Mathematics
2 answers:
lions [1.4K]2 years ago
7 0
The answer is 16…
because 6 •|• 3 is 2 and 2•7 is 14 then add them together. 2+14=16
NARA [144]2 years ago
4 0

Step-by-step explanation:

What is the molar mass of an element?

the total number of particles in one gram of the element

the mass of 6.02 x 1023 representative particles of the element

the number of amus (atomic mass units) in 6.02 x 1023 moles of the element

1.0 gram divided by the atomic weight of the element

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Veronica has been saving dimes and quarters and has a total of 86 coins worth $9.00. How many
taurus [48]
The answer to your question is 4.11 if I’m correct
8 0
2 years ago
If the very first chip had four transistors, use Moore’s law to calculate the number of transistors on a chip every two years ov
Elina [12.6K]
5+5 = the amount of females u don’t have because the females are not interested
4 0
3 years ago
Calculate the area of each circle
Triss [41]

Answer:

1.54 in²

Step-by-step explanation:

Given that,

→ Radius (r) = 0.7 in

Formula we use,

→ πr²

The area of the circle will be,

→ πr²

→ (22/7) × 0.7 × 0.7

→ (22/7) × 0.49

→ [ 1.54 in² ]

Hence, area of circle is 1.54 in².

8 0
2 years ago
Your office parking lot has a probability of being occupied of 1/3. You happen to find it unoccupied for nine consecutive days.
olasank [31]

Answer:

0.4

Step-by-step explanation:

Let X be the random variable that represents the number of consecutive days in which the parking lot is occupied before it is unoccupied. Then the variable X is a geometric random variable with probability of success p = 2/3, with probability function f (x) = [(2/3)^x] (1/3)

Then the probability of finding him unoccupied after the nine days he has been found unoccupied is:

P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9). For a geometric aeatory variable:

P (X> = 10) = 1 - P (X <10) = 0.00002

P (X> = 9) = 1 - P (X <9) = 0.00005

Thus, P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9) = 0.00002 / 0.00005 = 0.4.

6 0
3 years ago
Time spent using​ e-mail per session is normally​ distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that
liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 11, \sigma = 3

a. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 25, s = \frac{3}{\sqrt{25}} = 0.6

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.6}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.6}

Z = -0.33

Z = -0.33 has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.5 and 11 ​minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

Z = \frac{X - \mu}{s}

Z = \frac{11 - 11}{0.6}

Z = 0

Z = 0 has a pvalue of 0.5.

X = 10.5

Z = \frac{X - \mu}{s}

Z = \frac{10.5 - 11}{0.6}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 100, s = \frac{3}{\sqrt{100}} = 0.3

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.3}

Z = -0.67

Z = -0.67 has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0
3 years ago
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