No.
Tom forgot about the area of the top/roof, the floor and roof are different dimensions/areas, making his method incomplete.
He needs to find area of Roof, Floor then times height.
Thank you :)
can you mark me brainliest if possible, i’m like really desperate hahah thanks in advance
Answer:
one solution
Step-by-step explanation:
it has one solution because the slopes of the two equations(1x & 2x) are different, which means the lines of the two equations are not parallel, they have an intersection point(also means one solution).
Answer:
Step-by-step explanation:
Let the side of the square base be x
h be the height of the box
Volume V = x²h
13500 = x²h
h = 13500/x² ..... 1
Surface area = x² + 2xh + 2xh
Surface area S = x² + 4xh ...... 2
Substitute 1 into 2;
From 2; S = x² + 4xh
S = x² + 4x(13500/x²)
S = x² + 54000/x
To minimize the amount of material used; dS/dx = 0
dS/dx = 2x - 54000/x²
0 = 2x - 54000/x²
0 = 2x³ - 54000
2x³ = 54000
x³ = 27000
x = ∛27000
x = 30cm
Since V = x²h
13500 = 30²h
h = 13500/900
h = 15cm
Hence the dimensions of the box that minimize the amount of material used is 30cm by 30cm by 15cm
