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leonid [27]
3 years ago
8

4x-10+14+7x-10x+2 I just want to make sure I got it right

Mathematics
2 answers:
erastova [34]3 years ago
7 0
The answer is -9x +16
vichka [17]3 years ago
5 0

Combine like terms:

4x, 7x, -10x

-10, 14, 2

4x + 7x - 10x = x

-10 + 14 + 2 = 6

6 + x should be the correct answer.

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Write the relation as a set of ordered pairs.
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\left\begin{array}{c|l}T&\qquad w(t)\\1&\dfrac{1}{1^2}=1\implies 1.00\\\\2&\dfrac{1}{2^2}=\dfrac{1}{4}\implies 0.25\\\\10&\dfrac{1}{10^2}=\dfrac{1}{100}\implies 0.01\\\\50&\dfrac{1}{50^2}=\dfrac{1}{2500}\implies 0.0004\\\\100&\dfrac{1}{100^2}=\dfrac{1}{10000}\implies 0.0001\\\\200&\dfrac{1}{200^2}=\dfrac{1}{40000}\implies 0.000025\\\\500&\dfrac{1}{500^2}=\dfrac{1}{250000}\implies 0.000004\\\\1000&\dfrac{1}{1000^2}=\dfrac{1}{100000}\implies 0.000001\\\end{array}\right

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2 years ago
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3 years ago
How would I find all real solutions in x^4/3 -10^2/3 +21= 0
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Answer:

Step-by-step explanation:

This equation looks complicated.We have to make it easier

let's say x^2/3 = t  and  x^4/3 = t^2

     

      t^2-10t+21=0   [ we can factorize this equation as a (t-3)(t-7) ]

     

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But don't forget we have to find x not t so,

   t=x^2/3=3     ∛ x^2 = 3       x^2 = 9    x=3 or x= -3

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7 0
2 years ago
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