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sergeinik [125]
3 years ago
7

Three times a number increased by ten is equal to twenty less than six times the number. Find the number

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Let the number be x. "Three times a number increased by 10" is mathematically translated as

3x + 10

"is equal" is mathematically translated as twenty less than six times the number" is mathematically translated as

6x - 20

The whole sentence "Three times a number increased by ten is equal to twenty less than six times the number" is translated as

3x + 10 = 6x - 20

We now solve the above linear equation to find the number x

3x - 6x = - 20 - 10

- 3x = - 30

x = 10

Check answer

Three times a number increased by ten : 3 × 10 + 10 = 40

Twenty less than six times the number : 6 × 10 - 20 = 40

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Rina8888 [55]
 To do that you do 6*3=18 and then you have 18(x+2)  To find X we  distribute the 18

18x + 36 is what is left

Hope that helped:)
3 0
3 years ago
I need to help to solve this with answer?
Alinara [238K]

Answer:

137°

Step-by-step explanation:

7 0
3 years ago
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What is the product? One-eighth times three-elevenths 3 over 88 1 over 22 4 over 19 35 over 88
kipiarov [429]

Answer:

\frac{3}{88}

Step-by-step explanation:

Given

One-eighth times three-elevenths

Required

Solve

One-eighth means 1/8

Three-elevenths means 3/11

So, mathematically; the above expression is represented as thus:

\frac{1}{8} * \frac{3}{11}

To solve this, we simply multiply the numerator and the denominator together.

After multiplying these together, the next is to check if the resulting can be simplified

If yes,we simplify it and if otherwise, we live it like that.

So,

\frac{1}{8} * \frac{3}{11}

=\frac{1 * 3}{8 * 11}

= \frac{3}{88}

At this point, the fraction can't be simplified any further.

Hence,

\frac{1}{8} * \frac{3}{11} = \frac{3}{88}

3 0
3 years ago
Find the sum and express it in simplest form (6u-7c-6)+(-2u+4c)
Daniel [21]
4u+3c-6 is thats what its asking for? just puting the same variables together
4 0
3 years ago
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Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.
anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time²  =Speed¹ x Time¹ /Speed²

Time²  =Speed¹ x (Time² + 350 seconds  ) /Speed²

Time²  =0.9 x (Time² + 350 seconds  ) /1.9

Time²  =0,4737 x (Time² + 350 seconds  )

Time²  =0,4737 Time² + 165,79 seconds

Time²  - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0
3 years ago
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