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erma4kov [3.2K]
3 years ago
5

state of the triangles in each pair are similar. If so State how you know whether they are similar and complete the similarity s

tatement.​

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer: not similar

We don't have to work anything out, just look through the answers.   There are no angle measures or angle congruences indicated so none of the similarity theorems that use angles, namely SAS and AA, can be right.  That leaves not similar.

If we did want to check SSS similarity we have to check the corresponding ratios are equal.  Compare for example the ratio of the smallest sides to the ratio of the medium sides,

62/7 to 81/8

We can see those aren't equal because 8×62 is even and 7×81 is odd.

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lorasvet [3.4K]
C: Dilation because that is the only one that can increase the size of the figure. 
6 0
3 years ago
Read 2 more answers
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Please help me asap
astraxan [27]

Answer:

To find the inverse interchange the variables and solve for y.

Step-by-step explanation:

f−1(x)=6x−53(1+x)

6 0
1 year ago
Question 4 of 5
Alex787 [66]

The data set that has a variation, or mean absolute deviation, similar to the data set in the given dot plot is; Option D

<h3>How to Interpret Dot Plots?</h3>

The given dot plots options are as seen in the attached brainly link.

Now, the sample dot plot shows a total of 10 dots with 3 dots on 52, 2 dots on 53, 1 dots each on 54, 55, 56, 57, 58.

Looking at the options, the only one that represents the variation, or mean absolute deviation of the given sample is Option D.

Read more about Dot Plots at; brainly.com/question/22247061

#SPJ1

4 0
2 years ago
Five friends went to the movies. Total cost was $55.91. If the friends split the cost equally about how much did each person pay
Mars2501 [29]
Hello!

55.91 / 5 = 11.182

You can round that to 11.18

So, each person paid about $11.18.
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3 years ago
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