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bazaltina [42]
4 years ago
8

Solve for a. 4a+5=2+3.5a

Mathematics
1 answer:
Mazyrski [523]4 years ago
4 0

Answer:

a =-6

Step-by-step explanation:

4a+5=2+3.5a

Subtract 3.5a from each side

4a-3.5a+5=2+3.5a-3.5a

.5a +5 = 2

Subtract 5 from each side

.5a +5-5 = 2-5

.5a = -3

Divide each side by .5

.5a/.5 = -3/.5

a =-6

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Which inequality represents all the values of x for y<(or equal to)-6(x-18)-2 when y=46
bearhunter [10]

The value of x is x ≤ 9 for which y ≤ -5(x - 18) - 2 when y = 43.

<h3>What are inequalities and their types?</h3>

Inequality is a relation that compares two numbers or other mathematical expressions in an unequal way.

The symbol a < b indicates that a is smaller than b.

When a > b is used, it indicates that a is bigger than b.

a is less than or equal to b when a notation like a ≤ b.

a is bigger or equal value of an is indicated by the notation a ≥ b.

The given inequality is y ≤ -5(x - 18) - 2.

Now the values of x when y = 43 is,

43 ≤ - 5(x - 18) - 2.

43 ≤ - 5x + 90 - 2.

43 - 88 ≤ - 5x.

- 45 ≤ - 5x.

5x ≤ 45.

x ≤ 9.

learn more about inequalities here :

brainly.com/question/11612965

#SPJ1

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1 year ago
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Find the fractional side lengths of a rectangle that has a perimeter of 64 5/6 inches.
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3 years ago
A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len
Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

Area = 135yd^2

L=3W - 12

Required

Determine the length of the rectangle:

Area is calculated as thus:

Area = L * W

Substitute 3W - 12 for L and 135 for Area

135= (3W - 12) * W

135= 3W^2 - 12W

Reorder:

3W^2 - 12W - 135= 0

Divide through by 3

W^2 - 4W - 45 = 0

Expand:

W^2  - 9W + 5W - 45 = 0

W(W  - 9) + 5(W - 9) = 0

(W + 5)(W-9) = 0

W + 5 = 0 or W - 9 = 0

W = -5 or W = 9

But width can't be negative

So:

W = 9

Recall that: L=3W - 12

L = 3 * 9 - 12

L = 15

<em>Hence, the length 15 yards</em>

4 0
3 years ago
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