Answer:
ST = 20
Step-by-step explanation:
Line segment RS and segment ST must add up to line segment RT
Step 1: Define
RS = 17
ST = x + 6
RT = 3x - 5
Step 2: Set up equation
mRS + mST = mRT
17 + x + 6 = 3x - 5
Step 3: Solve for <em>x</em>
x + 23 = 3x - 5
23 = 2x - 5
28 = 2x
x = 14
Step 3: Find mST
ST = x + 6
ST = 14 + 6
ST = 20
Answer:
Choose f(x) = 11x + 1
Step-by-step explanation:
Note that we will simply plug the value of 2 into the equation for February:
f(2) = 11(2) + 1 = 23
And plug the value of 6 into the equation for June:
f(6) = 11(6) + 1 = 67
Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:
f(3) = 11(3) + 1 = 34
f(4) = 11(4) + 1 = 45
f(5) = 11(5) + 1 = 56
Note, these values seems to be very close in approximation to the graph points for each month.
The other three functions return values that are just to far away from what are represented in the graph.
Cheers.
For the first quarter you would use the equation of $2000+(2000 times 0.08)=the money for the first quarter or $2160. the second quarters equation is $2000+(2000 times 0.08)2= the money for the second quarter or $2320. the thirds quarters equation is $2000+(2000 times 0.08)3= the money for the third quarter or $2480. The fourth quarters equation is $2000+(2000 times 0.08)4=the money for the fourth quarter or $2640.
Answer:
Only one solution
Step-by-step explanation:
Given:
2c + 4 - 3c = -9 + c + 5
Find:
Number of solution
Computation:
2c + 4 - 3c = -9 + c + 5
-c + 4 = -4 + c
-2c = -8
c = 4
Only one solution
Answer:
Step-by-step explanation:
Given
There are 10 men and 5 women in a conference room
total People=15
(a)Probability that the committee consists of 2 men and 2 women
we have to select from 10 men and 5 women
(b)Bob and Jane end up on the same committee
as bob and Jane are necessary to include so there are 4 women and 9 men left to select remaining 2 person
(c)Bob is in the committee but Jane is not
9 men and 4 women left to choose other 3 person
