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Brrunno [24]
3 years ago
8

How do you solve 5q-7=2/3

Mathematics
2 answers:
photoshop1234 [79]3 years ago
4 0
5q^{(3} -7^{(3}=\frac{2}{3} \\ \\ 15q -21=2 \\ \\ 15q=2+21 \\ \\ 15q=23 \\ \\ \boxed{q=\frac{23}{15}}
erastova [34]3 years ago
3 0
5q-7=\frac{2}{3}\ \ \ \ \ \ |add\ 7\ to\ both\ sides\\\\5q=7\frac{2}{3}\\\\5q=\frac{23}{3}\ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{q=\frac{23}{15}}
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Sunny_sXe [5.5K]

Answer:

\frac{27}{8}m^3 or 3.375m^3

Step-by-step explanation:

The formula for volume is Base * Height * Width; and the formula for area is Base * Height.

This problem mentions the structure is a cube and therefore it is assumed that every wall has the same area. Since there are 6 sides to a cube you divide the total amount of ft which make up this cube to know the area to each wall.

13.5 m/6 = 2.25 or \frac{9}{4} m per wall

With the area of each wall you can find the base and height:

base * height =  area

b=\sqrt{\frac{9}{4} } = \frac{3}{2}

base = \frac{3}{2}m

height = \frac{3}{2}m

since: base=height=width, the width also equals \frac{3}{2}m

volume = (\frac{3}{2})^3= \frac{27}{8}

sorry it took so long for you to get an answer

8 0
4 years ago
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Answer:

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7 0
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Answer:

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