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madam [21]
3 years ago
9

A caterer charges a service fee and a food fee with the total being less than $1000 determine the food fee if the service fee is

$75
Mathematics
1 answer:
kkurt [141]3 years ago
6 0

Answer:925

Step-by-step explanation:

1000-75

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Find the area of the trapezoid please help
Xelga [282]

Answer:  12 units squared

Step-by-step explanation:

base1=2

base2=4

height=4

The formula is b1 + b2 x h / 2

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4 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
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The distance between the two points should be 9/4 if I did my math correct. This is because if you have 4 - (-5) over -3 - (-7) then you would get 9/4.
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Find the center and radius of the circle represented by the equation below.
valina [46]

Answer:

radius 4

center (3,6)

Step-by-step explanation:

(x - h)^2 + (y - k)^2 = r^2

coordinates of the center (h, k) and the radius is (r)

x² + y²- 6x - 12y +29=0

x² - 6x + y²- 12y +29=0

(x² - 6x) + (y²- 12y) +29=0

complete the square

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(x-3)^2 + (y-6)^2 = 16

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cuemathcom

varsitytutors

3 0
2 years ago
Read 2 more answers
Which expression represents "the product of 8 squared and the difference of a number,n and 9"
Margarita [4]

Step-by-step explanation:

Below is an attachment containing the solution.

5 0
4 years ago
Consider the initial value problem 2ty′=4y, y(2)=−8. 2ty′=4y, y(2)=−8. find the value of the constant cc and the exponent rr so
Softa [21]
2ty'=4y
Replacing y'=dy/dt in the equation:
2t(dy/dt)=4y
Grouping terms:
dy/y=4dt/(2t)
dy/y=2dt/t
Integrating both sides:
ln(y)=2ln(t)+ln(c), where c is a constant
Using property logarithm:  b ln(a) = ln(a^b), with b=2 and a=t
ln(y)=ln(t^2)+ln(c)
Using property of logarithm: ln(a)+ln(b) = ln(ab), with a=t^2 and b=c
ln(y)=ln(ct^2)
Then:
y=ct^2
Using the initial condition: y(2)=-8
t=2→y=-8→c(2)^2=-8→c(4)=-8
Solving for c:
c=-8/4
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Then the solution is y=-2t^2
Comparing with the solution: y=ct^r
c=-2, r=2

Answer: T<span>he value of the constant c is -2 (c=-2) and the exponent r is 2 (r=2)</span>
 
5 0
4 years ago
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