All categories

3 years ago

What I need to know is how to find x and y values by representing the answers in simplest radical form where necessary

Mathematics

1 answer:

Maru [420]3 years ago

6 0

Answer:

x = 0.6623

y = 8

Image is attached for refernce of my solution

Step-by-step explanation:

In Δ DEF

By applying pythagoras theoram,

DE = $\sqrt{EF^{2} - DF^{2} }$

= $\sqrt{17^{2} - 15^{2} } = \sqrt{289 - 225} = \sqrt{64} =8$

∴ DE = 8

In Δ ABC

BC = y = 12 sin 30° = 6

AC = $\sqrt{3}$ + DE + x = $\sqrt{3}$ + 8 + x = 12 cos 30°

⇒ 9.73 + x = 10.39

You might be interested in

Please help and show work!!

Maurinko [17]

12 - x < 8

add x to both sides

12 - x + x < 8 + x

12 < 8 + x

re-write

8 + x > 12

Subtract 8 to both sides

8 + x - 8 > 12 - 8

x > 4

The graph B is matching the answer (x > 4)

So answer is B.

8 0

3 years ago

Read 2 more answers

Question 1 of 20

ludmilkaskok [199]

Answer:

A. The volume is the product of the area of the base, 5x(x + 3), and

the height, 2x - 1.

Step-by-step explanation:

Volume is defined as the product of the Length, Width, and Height,

V = L*W*H

The Length x Width is the Area of the Base

L*W = Area Base)

Therefore:

The (L*W) in the equation V = L*W*H can be replaced with [Area of the Base]

[Area of the Base]

[Area of the Base] = (5x)*(x+3) [(or 5x^2 + 15x)]

Volume = [Area of the Base]*H

Volume = [(5x)*(x+3)]*(2x-1)

The volume is the product of the area of the base, 5x(x + 3), and

the height, 2x - 1.

That looks a lot like the answer in A: "The volume is the product of the area of the base, 5x(x + 3), and the height, 2x - 1."

6 0

3 years ago

Write the following as an exponential expression.

gogolik [260]

Answer:

x^3/7

Step-by-step explanation:

In exponential form the number on the outside of the √ will be the denominator of the fraction.

3 0

3 years ago

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

3 years ago

What is (are) the x- interscepts of the function graphed above

Vilka [71]

Answer:

D. -4, -1, and 5

Step-by-step explanation:

X-intercepts are the values where your graph (function) crosses the x-axis.

So, on this graph-the pink line crosses the x-axis at these values: -4, -1, and 5.

7 0

3 years ago