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3 years ago

Gina is the costume manager for a large theater company. She has 12 different hats, including 2 helmets.

Mathematics

1 answer:

zzz [600]3 years ago

6 0

2 out of the 12 total are helmets so the probability would be 2/12 which simplifies to 1/6.

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Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

3 0

3 years ago

What is the slope of (1,-5) and (3,-17)

Nikitich [7]

m(slope)= change in y/change in x

m=-17-(-5)/3-1

m=17+5/2

m=22/2

m=11

5 0

3 years ago

4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the

s2008m [1.1K]

Answer:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = $2a$

where $a$ is called the semi-major axis.

In this case since the major axis is equal to 10 units:

$10=2a$

solving for the semi-major axis $a$ :

$a=10/2\\a=5$

and also the minor axis of an ellipse is represented as:

Minor axis = $2b$

where $b$ is called the semi-minor axis.

Since the minor axis has a length of 8 units:

$8=2b$

solving for b:

$b=8/2\\b=4$

Now we can use the equation for an ellipse centered at the origin (0,0):

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

and substituting the values for $a$ and $b$ :

$\frac{x^2}{5^2} +\frac{y^2}{4^2} =1$

and finall we simplify the expression to get the equation of the ellipse:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

5 0

3 years ago

Find the Value of a and b i dare u

fenix001 [56]

Well it's a dare so I guess I'll do it.

3 0

3 years ago

Identify the augmented matrix for the system of equations.

lord [1]

Answer:

The augmented matrix for the system of equations is $\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$ .

Step-by-step explanation:

This system consists in three equations with three variables ( $x$ , $y$ , $z$ ).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:

$\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$

The augmented matrix for the system of equations is $\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$ .

8 0

3 years ago