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Anarel [89]
4 years ago
13

(25) (4.12) (show steps)

Mathematics
1 answer:
Usimov [2.4K]4 years ago
8 0
Okay so we are using decimals and multiplying! :) 

25 doesn't have a decimal so, we add one and now it turns into this: 25.00

And now we align the decimals and it turns into this:

     25.00
×     4.12
---------------
       1.03

And remember, the bigger number always goes on top! :P

Hope this helps! 
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Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify t
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There is sufficient evidence to conclude that child booster seats meet the specific requirement.

Step-by-step explanation:

Sample: 697, 759, 1266, 621, 569, 432

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{4344}{6} = 724

Sum of squares of differences = 415616

S.D = \sqrt{\frac{415616}{5}} = 288.31

We are given the following in the question:  

Population mean, μ = 1000 hic

Sample mean, \bar{x} = 724

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, s = 288.31

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1000\text{ hic}\\H_A: \mu < 1000\text{ hic}

We use one-tailed(left) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{724 - 1000}{\frac{288.31}{\sqrt{6}} } = -2.344

Now, t_{critical} \text{ at 0.05 level of significance, 5 degree of freedom } = -2.015

Calculation the p-value from table,

P-value = 0.033

Since,                  

Since, the p value is lower than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that the measurement is less than 1000 hic.

Thus, there is sufficient evidence to conclude that child booster seats meet the specific requirement.

4 0
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