Six times a number is equal to eight more than five times the number

Larisa earns $7 per hour.she worked 40 hours at the regular rate, 3 hours at time and half, and 6 hours at double time.

VARVARA [1.3K]

Answer:

$6.07/hr. if I understand the question properly. See below.

Step-by-step explanation:

I don't see the question, but will assume we want to find Larisa's base pay. The $7/hr given is the average for the work sequence noted in the problem. If this is incorrect, ignore the answer.

==================================

Let x be Larisa's base salary. We are told, I think, that in one stretch of time Larisa earned an average of $7/hour. That was composed of:

Hours Rate($/hr)

40 x

3 1.5x

6 2x

49

Her total income over this period would be:

40x +3(1.5x) + 6(2x) [The hours worked times the pay rate for each period]

Her average income per hour would be:

(40x +3(1.5x) + 6(2x))/49

which we are told is $7/hr.

(40x +3(1.5x) + 6(2x))/49 = 7

40x + 4.5x + 12x = 343

56.5x = 343

x = $6.07/hr

6 0

1 year ago

Without exponents logc (xy^6z^-4) what is the equivalent expression

Sever21 [200]

By eliminating exponents, the logarithmic expression $\log_{c} x\cdot y^{6}\cdot z^{-4}$ is equivalent to the logarithmic expression $\log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z$ .

<h3>How to simplify logarithmic functions</h3>

In this problem we are supposed to eliminate all exponents of a logarithmic function by applying any of the following properties:

㏒ x · y = ㏒ x + ㏒ y
㏒ x/y = ㏒ x - ㏒ y
㏒ yˣ = x · ㏒ y

Now, we proceed to simplify the function:

$\log_{c} x\cdot y^{6}\cdot z^{-4}$

$\log_{c} x + \log_{c} y^{6} + \log_{c} z^{-4}$

$\log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z$

By eliminating exponents, the logarithmic expression $\log_{c} x\cdot y^{6}\cdot z^{-4}$ is equivalent to the logarithmic expression $\log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z$ .

To learn more on logarithms: brainly.com/question/24211708

#SPJ1

5 0

1 year ago

Help binomial distributions

Ymorist [56]

We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is

$P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}$

Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.

We can compute their probability and sum them: $\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788$

So, the answer is about 36.79%

3 0

3 years ago

On Aaron’s farm, 1/10 of the animals are cows, ⅖ of the animals are chickens,

Ray Of Light [21]

Answer:

There are 5 pigs on Aaron's farm

Step-by-step explanation:

1. Start with 40 animals

2. 1/10 of the animals are cows, so divide 40 by 10 and you will find that 4 of the animals are cows

3. 2/5 of the animals are chickens, so multiple 40 by 2 to get 80 and then divide 80 by 5 and you will find that 16 of the animals are chickens

4. Subtract the 4 cows and 16 chickens from the 40 total animals and you find there are 20 more animals that are neither cows nor chickens

5. Of the 20 remaining animals, 1/4 are pigs, so divide 20 by 4 and you will find that there are 5 pigs

6 0

3 years ago

Nancy bought a vase as wedding gift .The cost excluding vat was R250.How much must she pay with VAT inclusive

Anvisha [2.4K]

Step-by-step explanation:

VAT = 250*15%

VAT = 250*15/100

VAT = 37.5 therefore

total price add VAT =250+37.5

=287.5

5 0

2 years ago