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Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

3 0

3 years ago

There are 16 girls in the class this represents 80% of the class how many total students are there

Natali [406]

Answer:

20 total students. If I was one of the four guys in that class, man would that be fun.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Select the correct answer.

mariarad [96]

The answer to this Question is A

What is Absolute Value Function or so called Modulus Function or Mod function?

It is a function that takes all real values as input and returns same values but +ve in nature eg if you give input as 2, output will be 2 and if you give input as -2, you will get output 2 again

Solution:

We have expression Ix-5I + 2

we know that I anything I , called as mod of anything, is always greater than or equal to zero so if we take its minimum value as 0 and we get 0 + 2 = 2

means this expression cant be less than 2 hence it will be greater than or equal to 2

because minimum value of mod is 0 and we are adding 2 to it hence overall the expression will be greater than 2 only

To learn more about Absolute Value Function click the link:

brainly.com/question/28478005

#SPJ9

4 0

1 year ago

A researcher obtains t = 2.35 for a repeated-measures study using a sample of n = 8 participants. Based on this t value, what is

ZanzabumX [31]

Answer:

$p_v =2*P(t_{7}>2.35)=2*0.0255=0.051$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

Step-by-step explanation:

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but we can assume it as $\alpha=0.05$ . First we need to calculate the degrees of freedom like this:

$df=n-1=8-1=7$

The next step would be calculate the p value for this test. Since is a bilateral test or two tailed test, the p value would be:

$p_v =2*P(t_{7}>2.35)=2*0.0255=0.051$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

5 0

4 years ago

Kevin Sims bought a car for $12,000. A year is was worth 9,000. What was the percent decrease in value?

morpeh [17]

Answer:

in

Step-by-step explanation:

everybody hates Chris the lottery go exit the bathroom and eat a chicken nugget and and

5 0

3 years ago