All categories

3 years ago

Find the volume of each figure

Mathematics

2 answers:

konstantin123 [22]3 years ago

6 0

Answer:

1) 17.5×14×64

→ 1568 in³

2) volume= 0.5×3.6×10×5=

→ 90

3) d= 13, r=13/2= 6.5, h= 19

→ v= πr²h

→ π(6.5)²×19

→ 2521.91 mm³

4) Base Area= a+b/2×h

→ (37+15)/2×25.7 cm²

→26×25.7 cm²

→ 668.2 cm²

height= 20cm

voulme = 668.2×20

→ 13364 cm²

5) L×W×H

→ 25×7×18

→ 175×18

→ 3150 ft³

6) v=πr²h

→ π(3.2²)(8)

→ 81.92π

→ 257.36 km²

$------------$

hope it helps...

have a great day!!

mart [117]3 years ago

3 0

$\huge \boxed{1}$

→17.5 × 14 × 6.4

→1568 in³

$\huge \boxed{2}$

→0.5 × 3.6 × 10 × 5

→90 m³

$\huge \boxed{3}$

→ Diameter = 13 mm

→ Radius = 13/2 = 6.5

→ Height = 19 mm

→Volume => πr²h

=> 22/7 × (6.5)² × 19

=> 2521.91 mm³

$\huge \boxed{4}$

→ Base Area → a+b/2×h

→ (37+15)/2×25.7 cm²

→26×25.7 cm²

→ 668.2 cm²

(height= 20cm)

→volume => 668.2×20

→13364 cm²

$\huge \boxed{5}$

→Area→ L × B × H

→ 25×7×18

→ 175×18

→ 3150 ft³

$\huge \boxed{6}$

→Volume → πr²h

→ π(3.2²)(8)

→ 81.92π

→ 257.36 km²

$\boxed{Extra-Information}$

Always divide the diameter with 2 to get the radius.

Volume is expressed in cube³ unit.

$\bold \green{TheExtraterrestrial}$

You might be interested in

Which expressionism equivalent to -60 / 5 select all that apply 60 divided by negitive 5 60 times 1/5 60 times negitive 1/5 Negi

GaryK [48]

Answer:

Equivalent expressions

A) $\frac{60}{-5}$

C) $60\times (-\frac{1}{5})$

Step-by-step explanation:

Given expression :

$\frac{-60}{5}$

Choices given :

A) $\frac{60}{-5}$

B) $60\times \frac{1}{5}$

C) $60\times (-\frac{1}{5})$

D) $-60\times (-\frac{1}{5})$

To find the equivalent expression.

We will first evaluate the given expression.

$\frac{-60}{5}$

⇒ $-12$ [Quotient of a negative dividend and a positive divisor is always negative]

Evaluating each choice to select the equivalents.

A) $\frac{60}{-5}$

⇒ $-12$ [Quotient of a positive dividend and a negative divisor is always negative]

B) $60\times \frac{1}{5}$

⇒ $\frac{60}{5}$

⇒ $12$

C) $60\times (-\frac{1}{5})$

⇒ $-\frac{60}{5}$ [Product of a positive and a negative is always a negative]

⇒ $-12$

D) $-60\times (-\frac{1}{5})$

⇒ $\frac{60}{5}$ [Product of two negatives is always a positive]

⇒ $12$

∴ We see that the choices A and C are equivalent.

7 0

3 years ago

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = - $\sqrt{3}$

cos = $\frac{-\sqrt{3}}{3}$

Hope this helps!! :)

3 0

3 years ago

Read 2 more answers

Add and simplify: 9/16 + 1/2=?

kozerog [31]

9/16+ 1/2
= 9/16+ (1*8) / (2*8)
= 9/16+ 8/16 (common denominator is 16)
= (9+8)/16
= 17/16
= (16+1)/16
= 16/16+ 1/16
= 1+ 1/16
= 1 1/16

The final answer is 1 1/16~

8 0

3 years ago

Read 2 more answers

Ms. Johnson was grading Drake's test. Drake got 27 out of 30 questions correct. What percent is equivalent to the fraction of th

andreev551 [17]

27/30 as a percentage is 90%

5 0

3 years ago

Question Progress

mixas84 [53]

Answer:

Please check the attached figure!

Step-by-step explanation:

Part a)

Point A is located at the x-coordinate x=-4 and y-coordinate y=1.

Hence, the coordinates of point A = (-4, 1)

Part b)

Point B(3, -2) has been plotted and is shown in the attached figure.

It is clear from the attached diagram that point B is located at the x-coordinate x=3 and y-coordinate y=-2. Hence, the coordinates of point B = (3, -2)

Part C)

Point C has the same x-coordinate as point A i.e. x=-4 and the same y-coordinate as point B i.e. y=-2.

Hence, the coordinates of point C = (-4, -2). Point C is also plotted as shown in the diagram.

7 0

3 years ago