Answer:
the number of times in a month the train must be used, so that the total monthly cost without the pass is the same as the total monthly cost with the pass, is b. 24 times
Step-by-step explanation:
in normal purchase, train ticket (A) = $2.00
using frequent pass,
frequent pass (P) = $18
train ticket using frequent pass (B) = $1.25
Now, let assume the number of times in a month the train must be used = M
so,
A x M = P + (B x M)
$2.00 x M = $18 + ($1.25 x M)
($2.00 x M) - ($1.25 x M) = $18
M x ($2.00 - $1.25) = $18
M = $18 : $0.75
M = 24
Thus, the number of times in a month the train must be used is 24 times
Answer:
-x + 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define expression</u>
(2x + 4) + (-3x + 9)
<u>Step 2: Simplify</u>
- Combine like terms (x): -x + 4 + 9
- Combine like terms (Z): -x + 13
1. 12 pages
2. 1/8 miles in 1 minute
3. 2 gallons an hour
Hope these are the correct answers! :)
Step-by-step explanation:
No. of banana Cost Unit price
4 2 0.50
6 3 0.50
7 3.5 0.50
20 10 0.50
20 10 0.50
33 16.50 0.50
Cost = No of banana x unit price
Cost = 4 x 0.50 = 2
Cost = 6 x 0.50 = 3
Cost = 7 x 0.50 = 3.50
Cost = 20 x 0.50 = 10
No of banana = Cost / Unit price
No of banana = 10 / 0.50 = 20
No of banana = 16.50 / 0.50 = 33
