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3 years ago

Twelve less than a number y is 8? Please help

Mathematics

2 answers:

Fittoniya [83]3 years ago

8 0

Answer: Y = 20

Step-by-step explanation:

The equation to solve this problem is y - 12 = 8

In order to solve the equation you need to add 12 to each side -

Y = 20

You can then check your work - 12 less than 20 equals 8. This is correct, so you know that your answer is correct.

evablogger [386]3 years ago

7 0

Answer:

The answer is y = 20

Step-by-step explanation:

To find this, we need to turn it into an equation. Then we can follow the order of operations to solve.

y - 12 = 8

y = 20

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I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct

Bond [772]

Given the system of equations:

$\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}$

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

$\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}$

Step 2: Substitute the expression found for x in the first equation.

$\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}$

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

$\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}$

Then, divide both sides by 15.

$\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}$

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

$\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}$

Answer:

x = -9

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Also, you can graph the lines by choosing two points from each equation, according to the picture below.

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1 year ago

Find the distance between the points (-3, 11) and (5,5).<br> O 10<br> 2/10<br> o 2.17

german

Answer: d = 10

Step-by-step explanation:

The formula for calculating distance between two points is given by :

d = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

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$x_{2}$ = 5

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$y_{2}$ = 5

substituting the values , we have

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d = $\sqrt{(5+3)^{2}+(-6)^{2}}$

d = $\sqrt{(8)^{2}+(-6)^{2}}$

d = $\sqrt{64+36}$

d = $\sqrt{100}$

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