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3 years ago

Twelve less than a number y is 8? Please help

Mathematics

2 answers:

Fittoniya [83]3 years ago

8 0

Answer: Y = 20

Step-by-step explanation:

The equation to solve this problem is y - 12 = 8

In order to solve the equation you need to add 12 to each side -

Y = 20

You can then check your work - 12 less than 20 equals 8. This is correct, so you know that your answer is correct.

evablogger [386]3 years ago

7 0

Answer:

The answer is y = 20

Step-by-step explanation:

To find this, we need to turn it into an equation. Then we can follow the order of operations to solve.

y - 12 = 8

y = 20

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A 33 33 -ft ladder leans against a building so that the angle between the ground and the ladder is .

I am Lyosha [343]

Question:

A 33 foot ladder leans against a building so that the angle between the ground and the ladder is 75º. How high does the ladder reach up the side of the building?

Round to 2 decimal places feet.

Answer:

$H = 31.88$

Step-by-step explanation:

The question is illustrated using the attachment as a sketch.

We have that

$Ladder = 33ft$

$\theta = 75$

Required

Determine how high the ladder is to the building

Represent the length of the ladder with L and how high the ladder is on the building with H.

The relationship between L, H and $\theta$ is"

$Sin\theta = \frac{H}{L}$

Substitute values for L and $\theta\\$

$Sin(75) = \frac{H}{33}$

Make H the subject

$H = 33 * Sin(75)$

$H = 33 * 0.9660$

$H = 31.88$

<em>Hence, the height to which the ladder reaches is approximately 31.88ft</em>

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3 years ago

2. There are 367 students in a class. If two students are chosen at random, what is the probability in percentage that the two s

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Step-by-step explanation: Hope this helps

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3 years ago

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Evgen [1.6K]

Answer:

3.3 and 5

Step-by-step explanation:

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2 years ago

A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i

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Answer:

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

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And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The degrees of freedom first given by:

$df=n-1=12-1=11$

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

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1 year ago