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3 years ago

How do you solve this ???

Mathematics

1 answer:

galina1969 [7]3 years ago

3 0

First you have to figure out how much a video game costs and how much a used one costs
Then you plug in the costs of the video games into Janets equation 120=3x+y
(x= video games and y=used video games)
Then you subtract the cost of video games from 120 and then divide that answer by the cost of used video games and that should give you how many used video games she can get

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The length of a rectangle is 4 less than twice the width. If the perimeter of the rectangle is 130, find the length of the recta

Alchen [17]

Answer:

Let L be the length of the rectangle and w be the width of the rectangle.

"The lenght of a rectangle is one less than twice the width" means L=2W-1

Using perimeter formula of a rectangle which is P=2(L+W) you have:

P=2(L+W)

130=2(2W-1+W)

Solve equation above to find W

130=2(3W-1)

130=6W-2

130+2=6W

132=6W

W=22

From here you find L=2W-1=2x22-1=43

Only thing left is to find area A=LxW

4 0

3 years ago

5 times a number increased by 4 is at least<br> nineteen

Anna35 [415]

Answer:

5(x+4) ≥ 19

x ≤ -1/5

Step-by-step explanation:

5(x+4) ≥ 19

5x + 20 ≥ 19

5x ≤ -1

x ≤ -1/5

5 0

3 years ago

An exam consists of 10 true-or-false questions. If a student guesses at every answer, what is the probability that he or she wil

zysi [14]

This can be solved by using the binomial distribution. The probability of guessing correctly is 0.5, and the probability of making a wrong guess is also 0.5.
$P(6\ correct)=10C6\times(\frac{1}{2})^{6}\times(\frac{1}{2})^{4}=\frac{210}{1024}=0.205$

5 0

3 years ago

statistical models predict that price p( in dollars) of a new smartphone will change according to the function p=900-4t^2. where

Gre4nikov [31]

we are given

$p=900-4t^2$

where

price p( in dollars) of a new smartphone

t is the number of months since January

now, we can solve for t

step-1:

Add both sides by 4t^2

$p+4t^2=900-4t^2+4t^2$

$p+4t^2=900$

step-2:

Subtract both sides by p

$p+4t^2-p=900-p$

$4t^2=900-p$

step-3:

divide both sides by 4

$\frac{4t^2}{4} =\frac{900-p}{4}$

$t^2=\frac{900-p}{4}$

$t^2=225-0.25p$

step-4:

Take sqrt both sides

$\sqrt{t^2} =\sqrt{225-0.25p}$

$t=\sqrt{225-0.25p}$

so, we get

$t=\sqrt{225-0.25p}$ ..............Answer

7 0

3 years ago

What is the area? Round to the nearest tenth

Tamiku [17]

Answer:

60.8 mm^2

Step-by-step explanation:

Remark

You have to assume that the left and right sides are both 9.3. The question is undoable without that assumption.

Next, you have to assume that The top is 7.8 mm across and both ends meet 9.3 at right angles. Again if that is not true, the problem can't be done. Sometimes people making these questions make errors which you are asked to correct.

Solution

So let's assume that everything I've assumed is correct.

Find the area of the rectangle.

Area = L*W

L = 9.3

W = 7.8

Area = 7.8 * 9.3

Area = 72.54 Do your rounding at the end.

Now find the are of the triangle that has been cut out.

The height = 3

The base = 7.8

Area = 1/2 b * h

Area = 1/2 7.8 * 3

Area = 11.7

The area of the figure = area of the rectangle - the triangle's area

Figure Area = 72.54 - 11.7

Figure Area = 60.84

6 0

3 years ago