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AleksandrR [38]
4 years ago
14

Look at the table showing different prices for oranges.

Mathematics
2 answers:
BaLLatris [955]4 years ago
5 0

Answer:

Price B, price A, price C

Step-by-step explanation:

I took the test.

RideAnS [48]4 years ago
3 0
The order for least to greatest unit rate would be Price B, Price A and then Price C. hope this helps:)
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Choose the possible solutions to the given inequality: x < 10.5
Blizzard [7]

Answer:

10 is the only one i'm pretty sure

Step-by-step explanation:

Because < is the less than symbol and 10 is the only number less than 10.5

3 0
3 years ago
An orchard has 1,064 trees arranged in 28 rows.
Bess [88]

Answer:

The Answer is B my fellow brainly students

IM TELLING YOU THE TRUTH

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Step-by-step explanation:


3 0
4 years ago
100 POINTS!! HELP!!!! BRAINLIEST ANSWER
Black_prince [1.1K]

The turning point is (3,3). The x to make the absolute value negative would be 2. The ordered pair would then be (0,3)

8 0
3 years ago
Read 2 more answers
Gummi bears come in twelve flavors, and you have one of each flavor. Suppose you split your gummi bears among three people (Adam
aliina [53]

Step-by-step explanation:

From the given gummi bear, the chance that Adam is selected for any draw is 1/3 as well as the chance he is not selected at any draw is 2/3.

a). The probability of Adam getting exactly three gummi bears = P(Adam gets selected at 3 draws and not selected at the remaining 9 draws)

= $ (\frac{1}{3})^3 (\frac{2}{3})^9 = \frac{2^9}{3^{12}} $

Now, the 3 draws where Adam gets selected can be any 3 out of 12 draws in $ {\overset{12}C}_3 $ = 220

Thus, probability of Adam getting three gummi bears = $ 220 \times \frac{2^9}{3^{12}} $

                                                                                                = 0.21186

b). Probability that Adam will get the three gummi bears given each person will received at the most 1 gummi bear

= P(of the remaining 9 draws after assigning one gummi bear to each one, Adam gets selected at 2 draws and not selected at 7 draws) = $ {\overset{9}C}_2 (\frac{1}{3})^2 (\frac{2}{3})^7 $

                                                                                               = 0.23411

c). Let X = Number of the gummi bears which Adam will get. Then, X = number of draws out of 12 draws Adam gets selected and X ~ B(12, 1/3). So,  Adam will get gummi bears= mean of B(12, 1/3) = 12 x (1/3) = 4

d). Let Y = Number of the gummi bears that Adam will get, given each person will received at the most 1 gummi bear Then, Y = number of draws Adam gets selected in the remaining 9 draws and Y ~ B(9, 1/3). So, the expected number of bears that Adam gets given each person received at least 1 gummi bear

= 1 + mean of B(9, 1/3) = 4

e). When every one gets atleast one gummi bear, the new sample size will be 9 and so we can say that there is a reduction in variance.

8 0
3 years ago
6.875- Negative (-1/4)
kherson [118]

Answer:

7.125

Step-by-step explanation:

6.875 - (-\frac{1}{4})

Two negatives multiply to give a positive and thus we can remove the parenthesis

6.875 +\frac{1}{4}

Converting fractions to decimals.

6.875+0.25

=7.125

7 0
3 years ago
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