If 2 dozens of eggs cost #300. How much will 5 eggs cost?

PLEASE HELP NEED ANSWERS ASAP!

gavmur [86]

The greatest common factor of 20 and 14 is 2.

The greatest common factor of x^3 and x is x.

The answer is C. 2x

4 0

3 years ago

Read 2 more answers

Receiving a high school diploma is known to improve your employment options. False True

matrenka [14]

True. There are more options available as to someone who doesn’t get their high school diploma.

7 0

3 years ago

Given the function f(x) = 4(x+3) − 5, solve for the inverse function when x = 3. (1 point)

atroni [7]

the function f(x) = 4(x+3) − 5

Lets find the inverse function f^-1(x)

step 1: Replace f(x) with y

y = 4(x+3) − 5

step 2: Replace x with y and y with x

x = 4(y+3) - 5

step 3: Solve for y

x = 4(y+3) - 5

x = 4y +12 -5

x= 4y + 7 (subtract 7 on both sides)

x - 7 = 4y (divide by 4 on both sides)

$\frac{x-7}{4}=y$

$f^{-1}(x)=\frac{x-7}{4}$

Given : x = 3

We plug in 3 for x in the inverse function

$f^{-1}(x)=\frac{3-7}{4}$ = -1

the inverse function when x = 3 is -1

6 0

3 years ago

Read 2 more answers

The concentration C of certain drug in a patient's bloodstream t hours after injection is given by

frozen [14]

Answer:

a) The horizontal asymptote of $C(t)$ is $c = 0$ .

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.

c) The time at which the concentration is highest is approximately 1.291 hours after injection.

Step-by-step explanation:

a) The horizontal asymptote of $C(t)$ is the horizontal line, to which the function converges when $t$ diverges to the infinity. That is:

$c = \lim _{t\to +\infty} \frac{t}{3\cdot t^{2}+5}$ (1)

$c = \lim_{t\to +\infty}\left(\frac{t}{3\cdot t^{2}+5} \right)\cdot \left(\frac{t^{2}}{t^{2}} \right)$

$c = \lim_{t\to +\infty}\frac{\frac{t}{t^{2}} }{\frac{3\cdot t^{2}+5}{t^{2}} }$

$c = \lim_{t\to +\infty} \frac{\frac{1}{t} }{3+\frac{5}{t^{2}} }$

$c = \frac{\lim_{t\to +\infty}\frac{1}{t} }{\lim_{t\to +\infty}3+\lim_{t\to +\infty}\frac{5}{t^{2}} }$

$c = \frac{0}{3+0}$

$c = 0$

The horizontal asymptote of $C(t)$ is $c = 0$ .

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.

c) From Calculus we understand that maximum concentration can be found by means of the First and Second Derivative Tests.

First Derivative Test

The first derivative of the function is:

$C'(t) = \frac{(3\cdot t^{2}+5)-t\cdot (6\cdot t)}{(3\cdot t^{2}+5)^{2}}$

$C'(t) = \frac{1}{3\cdot t^{2}+5}-\frac{6\cdot t^{2}}{(3\cdot t^{2}+5)^{2}}$

$C'(t) = \frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right)$

Now we equalize the expression to zero:

$\frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right) = 0$

$1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} = 0$

$\frac{3\cdot t^{2}+5-6\cdot t^{2}}{3\cdot t^{2}+5} = 0$

$5-3\cdot t^{2} = 0$

$t = \sqrt{\frac{5}{3} }\,h$

$t \approx 1.291\,h$

The critical point occurs approximately at 1.291 hours after injection.

Second Derivative Test

The second derivative of the function is:

$C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}-\frac{(12\cdot t)\cdot (3\cdot t^{2}+5)^{2}-2\cdot (3\cdot t^{2}+5)\cdot (6\cdot t)\cdot (6\cdot t^{2})}{(3\cdot t^{2}+5)^{4}}$

$C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}- \frac{12\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}$

$C''(t) = -\frac{18\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}$

If we know that $t \approx 1.291\,h$ , then the value of the second derivative is:

$C''(1.291\,h) = -0.077$

Which means that the critical point is an absolute maximum.

The time at which the concentration is highest is approximately 1.291 hours after injection.

5 0

3 years ago

A family wants to rent a car to go on vacation. Company A charges $30.50 and 9 cents per mile. Company B charges $70.50 and 14 c

Helen [10]

Answer:

$(39.24x)

Step-by-step explanation:

We need to find out their difference for one mile before calculating their difference for x miles.

Difference per mile = ($70.50 + $0.14) - ($30.50 + $0.90)

= $70.64 - $31.40

= $39.24

Difference for x miles = $39.24 × x miles

= $(39.24x)

4 0

3 years ago