Answer:
we have
f(x)=x-6f(x)=x−6 -----> equation A
This is a linear equation with slope m=1m=1 and a y-intercept equal to -6−6
g(x)=x+6g(x)=x+6 -----> equation B
This is a linear equation with slope m=1m=1 and a y-intercept equal to 66
The function f(x) and g(x) are parallel lines
we know that
h(x)=f(x)+g(x)h(x)=f(x)+g(x)
Substitute
h(x)=x-6+x+6h(x)=x−6+x+6
h(x)=2xh(x)=2x
This is a linear equation with slope m=2m=2 that passes through the origin ( represent a direct variation)
Using a graphing tool
see the attached figure
Answer:
<h2>See the explanation and the image.</h2>
Step-by-step explanation:
The inequality means .
y = 0, satisfies the above inequality, so the arrows will be towards the x axis.
Now, we need to draw 5x < 8 + 4y.
First, lets draw the equation of 5x = 8 + 4y.
y = 1 gives x = 2.4 & y = 0 gives x = 1.6.
Hence, the above equation passes through (2.4, 1) and (1.6, 0).
The point (0, 0) satisfies the inequality 5x < 8 + 4y. Hence, the arrows will be towards the origin.
The solution will be the area of APQ except any point on PQ, as PQ is nothing but the line 5x = 8 + 4y.
<span>Let x be the speed of the first car, then (x + 10) is the speed of the second car.
We can write the equation by the condition of the problem:
</span>
mph s<span>peed of the first car
</span>
Then 30+10=40 mph speed of the second car
Answer: 30mph and 40 mph.
<span>I hope this helps.</span>
X should be equal to 1/6
I think this is right :P