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3 years ago

At the bank, Derek made 7 withdrawals, each in the same amount. His brother, John, made 5 withdrawals,

1 answer:

5 0

At the bank, Derek made 7 withdrawals, each in the same amount. His brother, John, made 5 withdrawls, each in the same amount.

Let x be the amount of one of Derek's withdrawals

Each of John's withdrawals was $5 more than each withdrawal that Derek made.

x + 5 is t the amount of one of John's withdrawals

Derek made 7 withdrawals

So amount withdraw 7 times = 7x

John made 5 withdrawals

So amount withdraw 5 times = 5(x+5)

Both Derek and John withdrew the same amount of money in the end

(A)7x = 5(x+5)

(B) Solve for x

7x = 5x + 25

Subtract 5x from both sides

2x = 25

Divide by 2

x = 12.5

we plug in 12.5 for x in 7x= 5x + 25

7(12.5) = 5(12.5) + 25

87.5 = 62.5+ 25

87.5 = 87.5

(D) Each brother withdrawal 87.5 dollars

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Solving for x on the question - 2x + 3y = 32 |

Answer : x = $\frac{-3}{2}$ ⁻y + 16

Solving for y on the question - 2x + 3y = 32 |

Answer : y = $\frac{-2}{3}$ x + $\frac{32}{3}$

Solving for x on question - 5x - 4y = -81 |

Answer : x = $\frac{4}{5}$ y + $\frac{-81}{5}$

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<h2>Step-by-step explanation:</h2>

(Solving for x on question - 2x + 3y = 32)

2x + 3y = 32

Step 1: Add -3y to both sides.

2x + 3y + −3y = 32 + −3y

2x = −3y + 32

Step 2: Divide both sides by 2.

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x = $\frac{-3}{2}$ ⁻y + 16

(Solving for y on question - 2x + 3y = 32)

2x + 3y = 32

Step 1: Add -2x to both sides.

2x + 3y + −2x = 32+ −2x

3y = −2x + 32

Step 2: Divide both sides by 3.

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5x − 4y = −81

Step 1: Add 4y to both sides.

5x − 4y + 4y = −81 + 4y

5x = 4y − 81

Step 2: Divide both sides by 5.

$\frac{5x}{5}$ = $\frac{4y-81}{5}$

x = $\frac{4}{5}$ y + $\frac{-81}{5}$

(Solving for y on question - 5x - 4y = -81 )

5x − 4y = −81

Step 1: Add -5x to both sides.

5x − 4y + −5x = −81 + −5x

−4y = −5x − 81

Step 2: Divide both sides by -4.

$\frac{-4y}{-4}$ = $\frac{-5x-81}{-4}$

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