Answer:
y = 4
Step-by-step explanation:
2x + 3y = 6
2x + y = -2
Let's set the second equation equal to y. This means that y will be alone on one side of the equal sign.
2x + y = -2
Subtract 2x from both sides.
y = -2x - 2
Now that we have y as an expression, plug it into the first equation.
2x + 3y = 6
2x + 3(-2x - 2) = 6
Distribute the 3 across the parentheses by multiplying.
2x - 6x - 6 = 6
Combine like terms.
-4x = 12
Divide both sides by -4.
x = -3
Now we have solved x.
To solve for y, plug x back into one of the equations.
y = -2x - 2
y = -2(-3) - 2
Multiply.
y = 6 - 2
Subtract.
y = 4
Check your answer by plugging both values back into the original equations.
2x + 3y = 6
2(-3) + 3(4) = 6
Multiply.
-6 + 12 = 6
Add.
6 = 6
Your answer is correct.
Hope this helps!
Original price $24.99
Now it's on sale with 30% off
So the price now will be 24.99 - 30% of 24.99
Or we can say that it will be 70% of the initial price
So:
24,99 . 70% = 24,99 . 70/100 = 17,493
The price will be $17,493
Answer:
The margin of error M.O.E = 2.5%
Step-by-step explanation:
Given that;
The sample size = 1500
The sample proportion
= 0.60
Confidencce interval = 0.95
The level of significance ∝ = 1 - C.I
= 1 - 0.95
= 0.05
The critical value:
(From the z tables)
The margin of error is calculated by using the formula:




M.O.E = 0.02479
M.O.E ≅ 0.025
The margin of error M.O.E = 2.5%
The air resistance acting on the un-crumbled sheet is greater.