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3 years ago

Can someone help me?

Mathematics

1 answer:

jonny [76]3 years ago

3 0

Answer:I think it d

Step-by-step explanation:

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Solve for c 4(3+c)+c=c+4

Sonja [21]

Answer:

c = -2

Step-by-step explanation:

Given equation is :

4(3+c)+c=c+4

12 + 4c + c = c + 4

12 + 4c = 4 [dividing by 4]

3 + c = 1 [adding and subtracting 3]

c = -2

6 0

3 years ago

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Fedrick salary varies directly with hour he works last week he earned 328.30 and worked 33.5 hours if he works this week what wi

stiks02 [169]

Answer:

Step-by-step explanation:

8 0

3 years ago

Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ

Georgia [21]

The y-intercept of a function is the point where the graph crosses the $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
The y-intercept is -13.5
The standard equation of the function is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

(a) The factors

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

$\mathbf{x = -3}$

$\mathbf{x = -9}$

Equate the above points to 0

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

(b) The y-intercept

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

(c) The standard form

In (a), we have:

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Multiply the above equations

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}$

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

Expand

$\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }$

$\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }$

Expand

$\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }$

Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

$\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }$

Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

3 0

2 years ago

Write the coefficient of x² in X/3 (6x-1/2)

Igoryamba

Answer:

The coefficient of x² in the expression is 2

x/3(6x-1/2) = 6x²/3 - x/6

= 2x² - x/6

Hope this helps

7 0

3 years ago

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What is an equation of the line that passes through the point (5,1)(5,1) and is parallel to the line x+y=9x+y=9?

disa [49]

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1) you have : x_1 =5 and y_1 =1

m the slope m= -1 (same slope for the line : x+y=9 because this lines are parallel and you can write y=-x+9

an equation for this line is : y-1 = -(x-5)

4 0

3 years ago