Answer:
5.
x + 2(x + 1) = 8 --> x = 2
y = 2 + 1 = 3
7.
3(9 + 2y) + 5y = 20 --> y = -7/11
x = 9 + 2(-7/11) = 85/11
9.
3(-1 - 2y) + 5y = -1 --> y = -2
x = -1 - 2(-2) = 3
Answer:
uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math
Step-by-step explanation:
Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes
1sr event: drawing an I ( there are 2 I); P(1st I) = 2/11
2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)
2nd event : P(also one I) = 1/10
P(selecting one I AND another I) is 2/11 x 1/10
P(selecting one I AND another I) =2/110 = 0.018
