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3 years ago

I need help on rhis pls fastttttttt fastttttttt pls stytyt y

Mathematics

2 answers:

zavuch27 [327]3 years ago

7 0

Answer:

60 slices

Step-by-step explanation:

Well, to start you must figure the amount of slices, to begin with. This is 9 x 8

this is = to 72.

Then you take 5/6 of 72/1 by multiplying across. to get 60

Lina20 [59]3 years ago

7 0

Uhhhhhhhhhhhhhhh unicorns

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??????????????????????

never [62]

Answer:

I belive the answer would be the first one. 2^28 x 3^20 x 9^4

Step-by-step explanation:

This is becasue you need to multiply the power on the outside of the parenthesis, (4). 7 times itself 4 times is 28, 5 times itself 4 times is 20, and then use the 4 for the 9. Hope this helps!

7 0

3 years ago

Tamara says she used the GCF to factor the expression 21x + 56xy as 7(3x + 8xy). Is she correct? Explain.

cestrela7 [59]

Answer:

Tamara incorrectly factored the whole expression.

Step-by-step explanation:

Note that

21x=3·7·x;
56xy=2·2·2·7·x·y.

Mark in bold all common factors, then GCF(21x,56xy)=7·x=7x.

Thus,

21x+56xy=7x(3+8y).

Hence, Tamara correctly found the GCF of numbers 21 and 56, but incorrectly factored the whole expression.

6 0

3 years ago

NEED HELP ASAP PLS DUE TODAY !!!

S_A_V [24]

Answer:

with what do you need help? if you took a picture i cant see it at all

Step-by-step explanation:

6 0

3 years ago

There are 10 pens in a box. There are x red pens in the box. All the other pens are blue. Jack takes at random two pens from the

expeople1 [14]

The probability that one of each color is selected is $\frac{10x - x^2}{45}$

<h3>Probabilities</h3>

The probability of an event is the chances of the said event

The given parameters are:

Total = 10
Red = x
Blue = 10 - x

<h3>Calculating the required probability</h3>

The probability that one of each color is selected is calculated as follows:

$P = P(Blue) \times P(Red) + P(Red) \times P(Blue)$

So, we have:

$P = \frac{10 - x}{10} \times \frac{x}{9} + \frac{x}{10} \times \frac{10 - x}{9}$

This gives

$P = \frac{x(10 - x)}{90} +\frac{x(10 - x)}{90}$

Take LCM

$P = \frac{2x(10 - x)}{90}$

Simplify the above expression

$P = \frac{x(10 - x)}{45}$

Expand

$P = \frac{10x - x^2}{45}$

Hence, the probability that one of each color is selected is $P = \frac{10x - x^2}{45}$