62.5 mg sample will remain after 240 days
Step-by-step explanation:
Given
Half-life = T = 60 days
The formula for calculating the quantity after n half lives is given by:
![N = N_0(\frac{1}{2})^n](https://tex.z-dn.net/?f=N%20%3D%20N_0%28%5Cfrac%7B1%7D%7B2%7D%29%5En)
Here
N is the final amount
N_0 is the initial amount
n is the number of half lives passed
The number of half lives are calculated by dividing the time for which the remaining quantity has to be found by half life
The quantity has to be calculated for 240 days so,
![n = \frac{240}{60}\\n = 4](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B240%7D%7B60%7D%5C%5Cn%20%3D%204)
Given
![N_0 = 1000\ mg](https://tex.z-dn.net/?f=N_0%20%3D%201000%5C%20mg)
Putting the values in the formula
![N = 1000 (\frac{1}{2})^4\\=1000 * \frac{1}{16}\\=\frac{1000}{16}\\=62.5\ mg](https://tex.z-dn.net/?f=N%20%3D%201000%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E4%5C%5C%3D1000%20%2A%20%5Cfrac%7B1%7D%7B16%7D%5C%5C%3D%5Cfrac%7B1000%7D%7B16%7D%5C%5C%3D62.5%5C%20mg)
Hence,
62.5 mg sample will remain after 240 days
Keywords: Half-life, sample
Learn more about half-life at:
#LearnwithBrainly
The volume of the box is length*width*height
So length*3cm*3cm=45cm³
Let
![l=](https://tex.z-dn.net/?f=l%3D)
the length of the box
We have
![l*3*3=45](https://tex.z-dn.net/?f=l%2A3%2A3%3D45)
⇒
![9l=45](https://tex.z-dn.net/?f=9l%3D45)
⇒
![l=5](https://tex.z-dn.net/?f=l%3D5)
So the length should be 5 cm.
Answer:
-30
Step-by-step explanation:
The answer is b because 3 (adults)x $8=24+7(the kids)x$5=$59.
Answer:
s= -5
Step-by-step explanation:
-50=10s
divide both by 10
-5=s